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Svetradugi [14.3K]
3 years ago
13

The solution for x2 + 2x + 8 ≤ 0 is

Mathematics
2 answers:
allochka39001 [22]3 years ago
7 0

The answer to this is an empty set!

Gre4nikov [31]3 years ago
6 0

Answer:


Step-by-step explanation:

Please use " ^ " for exponentiation:  x^2 + 2x + 8 ≤ 0.

Let's solve this by completing the square:

x^2 + 2x + 8 ≤ 0  =>  x^2 + 2x + 1^2 - 1^2 + 8 ≤ 0.  Continuing this rewrite:

                                    (x + 1)^2 + 7 ≤ 0

Taking the sqrt of both sides:   (x + 1)^2 = i*sqrt(7)

Then the solutions are x = -1 + i√7 and x = -1 - i√7

There's something really wrong here.  I've graphed your function, x^2 + 2x + 8, and can see from the graph that there are no real roots, but only complex roots.  Please double-check to ensure that you've copied down this problem correctly.

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For a question like this, all you have to do is remember that a percentage is simply a fraction expressed as a decimal. So, all we have to do is:
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I hope this helped and remember to please try and understand the maths that got the answer, not just writing the answer down :))
4 0
3 years ago
Solve the simultaneous equation<br> 4x-y=9 <br> 2x-3y= -23
MrMuchimi

Answer:

x = 5

y = 11

Step-by-step explanation:

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minus cancels out

x = 5

y = 4(5) -9

y = 20 - 9

y = 11

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3 years ago
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2

Step-by-step explanation:

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