Question

I will give brainliest!! THERE IS NO OTHER INFORMATION GIVEN!! In ⊙O, chord XY is 8 cm long and is 10 cm from O. What is the radius ⊙O?

Answer 1

Answer:

Step-by-step explanation:

perpendicular from center always bisects the chord of circle.

1/2 of chord=1/2×8=4 cm

$r=\sqrt{4^2+10^2} =\sqrt{16+100} =\sqrt{116} \approx 10.77 ~cm$

Answer 2

Answer:

radius ≈ 10.77 cm

Step-by-step explanation:

The segment from the centre O to the chord is a perpendicular bisector.

Thus 2 right triangles are formed with legs 10 cm and 4 cm ( half of XY )

The radius r is the hypotenuse.

Using Pythagoras' identity, then

r² = 4² + 10² = 16 + 100 = 116 ( take the square root of both sides )

r = $\sqrt{116}$ ≈ 10.77 cm ( to 2 dec. places )