Answer:
denial-of-service attack (DoS attack) and distributed denial-of-service attack (DDoS attack)
Explanation:
Denial-of-service attack -
It is a type of cyber attack , where the hacker can create a machine or any network resource , which is capable to disrupt the server of the host , with the help of the internet , is referred to as the denial of service attack .
The task is accomplished with by flooding the host with many superfluous requests , which can overload the system .
In case of the distributed denial-of-service attack , the flooding is done by many different sources .
Hence , from the given scenario of the question ,
The correct answer is denial-of-service attack (DoS attack) and distributed denial-of-service attack (DDoS attack) .
Answer:
The formula and value to this question is "=A1+A3+A4+A5 with value 100"
Explanation:
The explanation of the given question as follows:
- In question, it is defined that four cells that are "A1, A2, A3, and A4" contains value that are "10, 20, 30, and 40".
- To add these values we use addition formula that is "=A1+A2+A3+A4". it will give value 100.
- If the user inserts a new row that is "A2" and assigns a value in the cell that is "50" so, we use the above formula that adds values with these values we also use the value "100".
Answer:
This article shows how to use regex to remove spaces in between a String.
A string with spaces in between.
String text = "Hello World Java.";
We want to remove the spaces and display it as below:
Hello World Java.
1. Java regex remove spaces
In Java, we can use regex \\s+ to match whitespace characters, and replaceAll("\\s+", " ") to replace them with a single space.
Regex explanation.
`\\s` # Matches whitespace characters.
+ # One or more
StringRemoveSpaces.java
package com.mkyong.regex.string;
public class StringRemoveSpaces {
public static void main(String[] args) {
String text = "Hello World Java.";
String result = text.replaceAll("\\s+", " ");
System.out.println(result);
}
}
Output
Terminal
Hello World Java.
Answer:
numbers = 1:1:100;
for num=numbers
remainder3 = rem(num,3);
remainder5 = rem(num,5);
if remainder3==0
disp("Yee")
else
if remainder3 == 0 && remainder5 == 0
disp ("Yee-Haw")
else
if remainder5==0
disp("Haw")
else
disp("Not a multiple of 5 or 4")
end
end
end
end
Explanation:
- Initialize the numbers variable from 1 to 100.
- Loop through the all the numbers and find their remainders.
- Check if a number is multiple of 5, 3 or both and display the message accordingly.
