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ehidna [41]
3 years ago
11

Alison wants to add her company name at the bottom of every page in her document. Which option should she use?

Computers and Technology
2 answers:
MissTica3 years ago
8 0
Hi there!

The correct option is C. Footer. A footer is the bottom section of a page in a document. The difference between a footer and a footnote is that a footer appears on every page whereas a footnote appears only on one page.

-<span>ASIAX </span><span>  </span><span>Frequent Answerer</span>
pav-90 [236]3 years ago
5 0

The answer is footer!

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There Are Two Programs in this Question who will attempt first i will give brainliest ans reward and big points:-
Korolek [52]

Answer:

here you go ,could only do Question 2.try posting question 1 seperately maybe someone else can also try to help

Explanation:

Question 2.

#include <iostream>

using namespace std;

// class BankAccount

class BankAccount{

  

    // instance variables

    private:

        int accountID;

        int balance;

  

    public:

      

        // constructor

        BankAccount(int accountID, int balance){

            this->accountID = accountID;

            this->balance = balance;

        }

      

        // getters and setters

        void setAccoutnId(int accountID){

            this->accountID = accountID;

        }

      

        int getAccountId(){

            return accountID;

        }

      

        void setBalance(int balance){

            this->balance = balance;

        }

      

        int balanceInquiry(){

            return balance;

        }

};

class CurrentAccount : public BankAccount{

  

    public:

  

        // constructor

        CurrentAccount(int accountID, int balance):BankAccount(accountID,balance){

          

        }

      

        // function amount to withdraw

        void amountWithdrawn(int amount){

            setBalance(balanceInquiry()-amount);

        }

      

        // function to deposit amount

        void amountDeposit(int amount){

            setBalance(balanceInquiry()+amount);

        }

};

class SavingsAccount : public BankAccount{

  

    public:

      

        // constructor

        SavingsAccount(int accountID, int balance):BankAccount(accountID,balance){

          

        }

  

        // function amount to withdraw

        void amountWithdrawn(int amount){

            setBalance(balanceInquiry()-amount);

        }

      

         // function to deposit amount

        void amountDeposit(int amount){

            setBalance(balanceInquiry()+amount);

        }

      

      

};

int main()

{

    // calling function of Current Account

    cout<<"Current Account : "<<endl;

    CurrentAccount current(122,100000);

    current.amountWithdrawn(10000);

    cout<<"Your balance after withdraw : ";

    cout<<current.balanceInquiry()<<endl;

    current.amountDeposit(30000);

    cout<<"Your balance after deposit : ";

    cout<<current.balanceInquiry()<<endl;

    cout<<endl<<endl;

  

    // calling function of Savings Account

    cout<<"Savings Account : "<<endl;

    SavingsAccount saving(125,80000);

    saving.amountWithdrawn(5000);

    cout<<"Your balance after withdraw : ";

    cout<<saving.balanceInquiry()<<endl;

    saving.amountDeposit(20000);

    cout<<"Your balance after deposit : ";

    cout<<saving.balanceInquiry();

    return 0;

}

4 0
3 years ago
Se tiene un pilar de hormigón de 30 cm de lado y 5 m de altura. Presenta una densidad de 2400 kg/m3 y una resistencia a la compr
kakasveta [241]

Answer:

El pilar no podrá soportar una masa de 10 toneladas

Explanation:

La dimensión del pilar de hormigón se da de la siguiente manera;

La longitud del lado, s = 30 cm = 0,3 m

La altura del pilar, h = 5 m

La densidad del pilar, ρ = 2,400 kg / m³

La resistencia a la compresión del pilar, σ = 500 kg / m²

El área de la sección transversal del pilar, A = s² = 0.3 m × 0.3 m = 0.09 m²

La masa del pilar, m = ρ × A × h = 2,400 × 0.09 × 5 = 1,080

La masa del pilar, m = 1.080 kg

Tenemos;

\sigma = \dfrac{F}{A}

Dónde;

F = La carga aplicada

A = El área de la sección transversal

∴ F = A × σ

F = 0,09 m² × 500 kg / m² = 45 kg

Por tanto, la carga que el pilar puede soportar sin compresión = 45 kg <10 toneladas = 9.071,847 kg

El pilar no podrá soportar una masa de 10 toneladas.

6 0
3 years ago
Python 3 please hurry!!
user100 [1]

Answer:

Explanation:

6 0
3 years ago
CJ is developing a new website blogging about cutting-edge technologies for people with special needs. He wants to make the site
crimeas [40]

Answer:

CJ is developing a new website blogging about cutting-edge technologies for people with special needs. He wants to make the site accessible and user friendly. CJ wants to link to articles in his website. He has assigned specific values for each ID attribute. To link to that ID attribute, CJ must use an # before the ID value in his href statement.

Explanation:

In order to create an internal link, a link's href element must be assigned to a hash symbol #, including the value of the id attribute for the element that is to be to internally linked to, usually further down the page. Then, there is also a need to add the same id attribute to the element to be linked to.

An id refers to an  attribute that uniquely describes an element. Below is an example of an internal anchor link and its target element:

<a href="#contacts-header">Contacts</a>

3 0
3 years ago
C++ code-- Factorial Recursion
Aloiza [94]
Handle the print outside of the factorial function, which only needs one userVal when called.

int factorial( int foo )
{
  if( foo == 1 )
   return 1;
 else
   return( foo * factorial( foo - 1 ) );
}
3 0
3 years ago
Read 2 more answers
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