1 Subtract <span>11</span> from both sides
<span>y-1={3}^{x}<span>y−1=<span>3<span><span>x</span><span></span></span></span></span></span>
2 Use Definition of Common Logarithm: <span>{b}^{a}=x<span><span>b<span><span>a</span><span></span></span></span>=x</span></span> if and only if <span>log_b(x)=a<span>lo<span>g<span><span>b</span><span></span></span></span>(x)=a</span></span>
<span>\log_{3}{(y-1)}=x<span><span><span>log</span><span><span>3</span><span></span></span></span><span>(y−1)</span>=x</span></span>
3 Switch sides
<span><span>x=\log_{3}{(y-1)}<span>x=<span><span>log</span><span><span>3</span><span></span></span></span><span>(y−1)
HOPE THIS HELPS!!! will it?
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Answer:
x=4, y=9/7
Step-by-step explanation:
We will use the property that the opposite sides of a rectangle are equal
3(3y-1)=2(y+3)
9y-3=2y+6
7y=9
y=9/7
2x=4(x-2)
2x=4x-8
2x=8
x=4
Answer: ![\dfrac{3}{51}](https://tex.z-dn.net/?f=%5Cdfrac%7B3%7D%7B51%7D)
Step-by-step explanation:
![\text{Probability of any event}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}](https://tex.z-dn.net/?f=%5Ctext%7BProbability%20of%20any%20event%7D%3D%5Cdfrac%7B%5Ctext%7BFavorable%20outcomes%7D%7D%7B%5Ctext%7BTotal%20outcomes%7D%7D)
Given : The number of cards in a standard deck of cards = 52
The number of jack in a deck of cards = 4
The probability of drawing the first card as jack :-
![\dfrac{4}{52}=\dfrac{1}{13}](https://tex.z-dn.net/?f=%5Cdfrac%7B4%7D%7B52%7D%3D%5Cdfrac%7B1%7D%7B13%7D)
If there is no replacement , the the total number of cards left = 51
The number of jack is left = 3
Then , the probability of choosing a jack for the second card drawn :-
![\dfrac{3}{51}](https://tex.z-dn.net/?f=%5Cdfrac%7B3%7D%7B51%7D)
Thomas is 29 and Huilan is 37. 29+37= 66
Answer:
shifts up 1/2
Step-by-step explanation:
big brain