Answer:
0.000005178
Step-by-step explanation:
we test for the goodness of fit
h0; drink preferences not changed
h1: drink preferences changed
alpha = 0.05
we solve for the test statistics
the chsquare test was performed in the attachment
Chi square = (O-E)²/E
chisquare = 32.30188
degree of freedom = n -1 = 6-1 = 5
using the chi distribution function on excel i calculated the p value
CHIDIST(32.30188, 5) =
P-value = 0.000005178
pvalue is less than 0.05 so we reject null hypothesis and conclude that there is sufficient evidence that drink preferences are changed.
the chisquare calculation is in the attachment. Thank you!
Answer:
If 2/3 of the girls in class have brown eyes and 1/4 of the girls have blue eyes, what fraction of the girls in class have neither blue nor brown
Step-by-step explanation:
1) you have to find the difference between pipe A and pipe B, which is 6.40.
23.55-17.15=6.40
2) after finding the difference. You will take that difference and put it out of 23.55 and multiply by 100 to get your percentage. As so:
(6.40/23.55)(100)= 27.176% which rounds to 27% as a whole number.
Your answer is 27%. Hope that helps!