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Alex777 [14]
3 years ago
7

Help on #6 (an explanation would be great)

Mathematics
1 answer:
Gala2k [10]3 years ago
5 0

Answer:

− 7 i \sqrt{2}

Step-by-step explanation:

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URGENT! find the sum. the answer is not D​
otez555 [7]
<h3>Answer:  C)  -1/2</h3>

=============================================

Explanation:

We'll apply the derivative to get

g(x) = 4x^3 + 3x^2

g ' (x) = 3*4x^2 + 2*3x

g ' (x) = 12x^2 + 6x

Set that equal to 0 and solve for x. We do this to find where the horizontal tangents are located.

g ' (x) = 0

12x^2 + 6x = 0

6x(2x + 1) = 0

6x = 0 or 2x+1 = 0

x = 0 or x = -1/2

Adding those two said solutions yields us the final answer choice C

7 0
3 years ago
How much should Tabatha budget monthly for insurance that costs $956.89 for the entire year?
elixir [45]
$79.74083  is the answer hope i help you

i divided 956.89 in 12 so that was the answer
5 0
3 years ago
NEED HELP PLSS!!!<br><br><br><br> pls dont answer if you dont know
jek_recluse [69]

Answer:

the second one is 343 to the 5 power

Step-by-step explanation:

thats all i know

srry honey

5 0
3 years ago
Read 2 more answers
The price of an item has been reduced by 85% the original price was $95 what is the price of the item
Yanka [14]

Answer:

14.25

Step-by-step explanation:

95 x 0.85 = 80.75

95-80.75 = 14.25

3 0
3 years ago
Given that f(a+b)= f(a) + f(b) and f(x) is always positive, what os the value of f(0)?
FrozenT [24]
This is a strange question, and f(x) may not even exist. Why do I say that? Well..

[1] We know that f(a+b) = f(a) + f(b). Therefore, f(0+0) = f(0) + f(0). In other words, f(0) = f(0) + f(0). Subtracting, we see, f(0) - f(0) = f(0) or 0 = f(0).

[2] So, what's the problem? We found the answer, f(0) = 0, right? Maybe, but the second rule says that f(x) is always positive. However, f(0) = 0 is not positive!

Since there is a contradiction, we must either conclude that the single value f(0) does not exist, or that the entire function f(x) does not exist.

To fix this, we could instead say that "f(x) is always nonnegative" and then we would be safe.
4 0
3 years ago
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