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OLga [1]
2 years ago
15

X - 1 = 30x^-1 solve for x

Mathematics
1 answer:
k0ka [10]2 years ago
8 0

Answer:

x=−5 or x=6

Mark me as Brainiliest

Step-by-step explanation:

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I need some help if you could
Fed [463]

Step-by-step explanation:

35A) arc AC = 360-(100+110+80)=

360-290 = 70°

35B) <em>L</em><em> </em>D = ½× 70 = 35°

35C) <em>L</em><em> </em>AEC = ½(100+70)=½×170= 85°

35D) <em>L</em><em> </em>P = ½(100-70) = ½×30 = 15°

5 0
3 years ago
WILL MARK BRANLIEST!!the tables below shows the values of y corresponding to different values of x
Kitty [74]

Answer: I'm pretty sure that it´s C but Im not sure.

Sorry if that's wrong.

7 0
3 years ago
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Of the following options, what could be a possible first step in solving the equation 3x − 1 = 2x + 4? Combining like terms, 3x
faust18 [17]
<span>Subtracting 2x from both sides of the equation would be a reasonable first step in solving this equation as it properly combines like terms to the left side of the equation. It quickly shows that the next step would be adding 1 to both sides of the equation, which would have us arrive at the answer of x = 5.</span>
8 0
3 years ago
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Which numbers in Set A = {−7, −4, 2, 14, 21, 34, 42} are elements of both Set B and Set C, shown below? Set B = {even numbers} S
sweet [91]

Answer:

14, 42

Step-by-step explanation:

Set A = {−7, −4, 2, 14, 21, 34, 42}

Set B = {even numbers}

Set C = {multiples of 7}

There is only one question asked

Which numbers in Set A are elements of both Set B and Set C,

We need it to be even and a multiple of 7

14 is even and a multiple of 7  and 42 is even and a multiple of 7

5 0
3 years ago
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What function corresponds to the ordered pairs shown in the table?
Anettt [7]

well, we know it's a line, and to get the equation of any line all we need is two points, let's pick two from the table hmmmm say let's use (-3 , -7) and (3 , 11)

(\stackrel{x_1}{-3}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{11}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{11}-\stackrel{y1}{(-7)}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{(-3)}}}\implies \cfrac{11+7}{3+3}\implies \cfrac{18}{6}\implies 3

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-7)}=\stackrel{m}{3}(x-\stackrel{x_1}{(-3)}) \\\\\\ y+7=3(x+3)\implies y+7=3x+9\implies y = 3x+2

6 0
2 years ago
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