The fastest time is 57.50 and the slowest time is 58.49.
The range of the primary phone data is 0.28.
The range of the secondary phone data is 0.73.
The median of the secondary phone data is 0.48 g larger than the median of the primary phone data.
To find the range of the primary phone data, subtract the largest and the smallest values:
0.35 - 0.07 = 0.28
To find the range of the secondary phone data, subtract the largest and the smallest values:
1.18 - 0.45 = 0.73
To find the median of the primary phone data, arrange the data from least to greatest and then find the middle value:
0.07, 0.08, 0.1, 0.1, 0.12, 0.13, 0.14, 0.22, 0.35 - the middle is 0.12
To find the median of the secondary phone data, arrange the data from least to greatest and then find the middle value:
0.45, 0.45, 0.5, 0.6, 0.6, 0.68, 0.82, 0.91, 1.18 - the middle is 0.6
The median of the secondary phone data, 0.6, is 0.6-0.12 larger than the median of the primary phone data; 0.6-0.12 = 0.48
Answer:
15% × 7 = 1.05
32,000 - 1.05 = 31,998.95
31,998.95 ‐‐‐‐‐> 31,999
$31,999
(If you don't need to simplify, the answer would be $31,998.95, but I did it just incase you do)
Step-by-step explanation:
For part A, you simply add the two functions a(x) and b(x). The resulting function is then (a+b)(x) = 5x +2.
For part B, you multiply the functions a(x) and b(x). Using the FOIL method, we obtain, 6x^2 -24x + 20x - 80. Simplifying, we get, (a*b)(x) = 6x^2 -4x - 80.
For part C, you replace x in the function a(x) with the expression from b(x). This results to: a[b(x)] = 3(2x - 8) +10. Simplifying, a[b(x)] = 6x - 14.
