Question

Write the equation of a line in standard form that has x-intercept (−P, 0) and y-intercept (0, R).

Answer 1

Answer:

$Rx-Py+PR=0$.

Step-by-step explanation:

The standard form of a line is

$ax+by+c=0$

It is given that x-intercept of the line is (−P, 0) and y-intercept is (0, R).

So, the equation of line is

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

$y-0=\dfrac{R-0}{0-(-P)}(x-(-P))$

$y=\dfrac{R}{P}(x+P)$

$Py=R(x+P)$

$Py=Rx+PR$

$0=Rx-Py+PR$

$Rx-Py+PR=0$

Therefore, the required equation of line is $Rx-Py+PR=0$.