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kiruha [24]
2 years ago
8

According to the Pew report, 14.6% of newly married couples in 2008 reported that their spouse was of another race or ethnicity

(CNNLiving, June 7, 2010). In a similar survey in 1980, only 6.8% of newlywed couples reported marrying outside their race or ethnicity. Suppose both of these surveys were conducted on 120 newly married couples. Use Table 1.
a.
Specify the competing hypotheses to test the claim that there is an increase in the proportion of people who marry outside their race or ethnicity.

H0: p1 − p2 ≤ 0; HA: p1 − p2 > 0
H0: p1 − p2 = 0; HA: p1 − p2 ≠ 0
H0: p1 − p2 ≥ 0; HA: p1 − p2 < 0
Mathematics
1 answer:
sweet [91]2 years ago
3 0
Shisiekkd. Wklwlwl kalwow wish is owl am dh Wii’s all wish wishfully usnan2839 7 hessian
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Park rangers notice a negative correlation between the number of available campsites in a park and the amount of litter on the p
galben [10]
The answer is The number of visitors to the park.
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3 years ago
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Suppose a basketball player has made 231 out of 361 free throws. If the player makes the next 2 free throws, I will pay you $31.
statuscvo [17]

Answer:

The expected value of the proposition is of -0.29.

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either the player will make it, or he will miss it. The probability of a player making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Suppose a basketball player has made 231 out of 361 free throws.

This means that p = \frac{231}{361} = 0.6399

Probability of the player making the next 2 free throws:

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.6399)^{2}.(0.3601)^{0} = 0.4095

Find the expected value of the proposition:

0.4095 probability of you paying $31(losing $31), which is when the player makes the next 2 free throws.

1 - 0.4059 = 0.5905 probability of you being paid $21(earning $21), which is when the player does not make the next 2 free throws. So

E = -31*0.4095 + 21*0.5905 = -0.29

The expected value of the proposition is of -0.29.

3 0
2 years ago
Change the following mixed number to an improper fraction. Reduce if possible.<br><br> 7 81/1000
pogonyaev

The answer is 7081/1000

7 0
2 years ago
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What is the value of <br> 6x²+4x+8 when x =7
Ann [662]

Answer:

330

Step-by-step explanation:

6x²+4x+8

Let x=7

6 ( 7)^2 + 4(7) +8

6*49+ 28+8

294+28+8

330

8 0
3 years ago
Omar rented a truck for one day. There was a base fee of $17.95, and there was an additional charge of 98 cents for each mile dr
stiv31 [10]

The given question is incomplete. The complete question is:

Omar rented a truck for one day. There was a base fee of $17.95, and there was an additional charge of 98 cents for each mile driven. Omar had to pay $23 when he returned the truck. For how many mile did he drive the truck?

Answer: Omar drove the truck for 5.15 miles

Step-by-step explanation:

Base fee = 17.95 $

Additional charge per mile = 98 cents = 0.98 $     ( 100cents = 1$)

Now Omar payed = 22 $

Let the miles he travelled = x

Now , 17.95+0.98\times x=23

Solvimg for x :

x=5.15miles

Thus Omar drove the truck for 5.15 miles

5 0
2 years ago
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