Based on the Microsoft Excel data validation, the option that is not an Error Style for data validation is the <em><u>choice that does not show an error alert.</u></em>
Given that there is no option available, the best way to answer this question is to show the types of Error Styles for data validation available.
<h3>Different types of Error Style for data validation</h3>
- Stop style: this will bring the option of "Retry, " "Cancel, " and "Help."
- Warning style: this will show "Continue," with options of "Yes," "No," "Cancel," and "Help."
- Information Style: this will ask you to input the whole number with the option of "Ok," "Cancel," and "Help."
Hence, in this case, it is concluded that the Error Style for data validation is Stop, Warning, and Information Style.
Learn more about Error Style for data validation here: brainly.com/question/18497347
Answer:
The answer is: they are comparable to suit of hearts
Explanation:
The answer is: they are comparable to suit of hearts
Answer:
public static int greaterThanInt(int n){
return n+10;
}
Explanation:
This is a very simple method in Java. it will accept an argument which is an integer n and return n+10 since the question requires that an arbitrary integer greater than n be returned adding any int value to n will make it greater than n.
A complete java program calling the method is given below:
<em>import java.util.Scanner;</em>
<em>public class ANot {</em>
<em> public static void main(String[] args) {</em>
<em> Scanner in = new Scanner(System.in);</em>
<em> System.out.println("Please enter an integer");</em>
<em> int n = in.nextInt();</em>
<em> int greaterInt = greaterThanInt(n);</em>
<em> System.out.println("You entered "+n+", "+greaterInt+" is larger than it");</em>
<em> }</em>
<em> public static int greaterThanInt(int n){</em>
<em> return n+10;</em>
<em> }</em>
<em>}</em>
Answer:
Four times traveling 40,12345 mts
Explanation:
We can express this as a sum as follows
The first term is the dropping part and the second is the upward motion. this sums up to 40,12345 m after bouncing four times. As a program we could write using the while loop.
distance=0;
i:=0;
while distance<40 do
i:=i+1;
distance:=distance+ 
end while;
Here the answer is in i and the closest distance traveled after reaching 40 is in the variable distance.
Answer:
try counting how many numbers there are to get to 5 which would be 4 then count how many numbers there to get 10 which is 5 and so on
