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kykrilka [37]
3 years ago
9

Please help will mark brainly

Mathematics
1 answer:
katrin2010 [14]3 years ago
3 0

Correct option d)0.61

<u>Step-by-step explanation:</u>

Here we have a number line from 0 to 1 . With every point at a equal distance of 0.10 from each other . Let's first mark the decimal 0.74 in number line . Now, Lets check one by one that which decimal is less than 0.74 . Remember , decimal will be less than 0.74 if point lies to the left side of 0.74.

<u>a)0.95:</u>

Decimal 0.95 lies to right side of 0.74 , So this decimal is not smaller than 0.74

<u>b)0.88:</u>

Decimal 0.88 lies to right side of 0.74 , So this decimal is not smaller than 0.74

<u>c)0.79:</u>

Decimal 0.79 lies to right side of 0.74 , So this decimal is not smaller than 0.74

<u>d)0.61:</u>

Decimal 0.61 lies to left side of 0.74 , So this decimal is smaller than 0.74

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Answer:

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So, i^2 = -1

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like ;

i^32 = (i^2)^16 = (-1)^16 =  -1 X -1 X-1 X -1 X-1 X -1 X-1 X -1 X-1 X -1 X-1 X -1 X-1 X -1 X-1 X -1 X

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3 years ago
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3 years ago
Three girls cut out decimal models of hundredths. Amber doesn't shade any of her models. Grace qualifies three fifths of a model
Varvara68 [4.7K]

Answer:

Amber = 0

Grace = 0.60

Marsha =1.70

Step-by-step explanation:

Given

<em>Decimal Grid = Hundredths</em>

Amber = None

Grace = \frac{3}{5}th

Marsha = 1 + \frac{7}{10}th

To solve for each:

We have:

For Amber:

Amber = 0 * 100

Amber = 0

For Grace:

Grace = \frac{3}{5}th

Grace = \frac{3}{5} * 100

Grace = \frac{300}{5}

Grace = 60

This means that Grace shaded 60 of the hundredth models.

Decimal shaded is:

Grace = 60 * \frac{1}{100}

Grace =\frac{60}{100}

Grace = 0.60

For Marsha:

Marsha = 1 + \frac{7}{10}th

Marsha = \frac{10 + 7}{10}th

Marsha = \frac{17}{10}th

Marsha = 1.7th

Multiply this by 100, to get the number of shaded

Marsha = 1.7 * 100

Marsha = 170

This means that Marsha shaded 170 of the hundredth models.

Decimal shaded is:

Marsha = \frac{170}{100}

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5 0
2 years ago
Which equation has the solutions x=1+or-square root of 5?
stiv31 [10]

We will proceed to solve each case to determine the solution of the problem.

<u>case a)</u> x^{2}+2x+4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}+2x=-4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}+2x+1=-4+1

x^{2}+2x+1=-3

Rewrite as perfect squares

(x+1)^{2}=-3

(x+1)=(+/-)\sqrt{-3}\\(x+1)=(+/-)\sqrt{3}i\\x=-1(+/-)\sqrt{3}i

therefore

case a) is not the solution of the problem

<u>case b)</u> x^{2}-2x+4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}-2x=-4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}-2x+1=-4+1

x^{2}-2x+1=-3

Rewrite as perfect squares

(x-1)^{2}=-3

(x-1)=(+/-)\sqrt{-3}\\(x-1)=(+/-)\sqrt{3}i\\x=1(+/-)\sqrt{3}i

therefore

case b) is not the solution of the problem

<u>case c)</u> x^{2}+2x-4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}+2x=4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}+2x+1=4+1

x^{2}+2x+1=5

Rewrite as perfect squares

(x+1)^{2}=5

(x+1)=(+/-)\sqrt{5}\\x=-1(+/-)\sqrt{5}

therefore

case c) is not the solution of the problem

<u>case d)</u> x^{2}-2x-4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}-2x=4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}-2x+1=4+1

x^{2}-2x+1=5

Rewrite as perfect squares

(x-1)^{2}=5

(x-1)=(+/-)\sqrt{5}\\x=1(+/-)\sqrt{5}

therefore

case d) is the solution of the problem

therefore

<u>the answer is</u>

x^{2}-2x-4=0

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2 years ago
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