Answer:
The ship is located at (3,5)
Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III
Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II
To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.
Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9
We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3
Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5
Based on the above, the position of the ship is (3,5).
Hope this helps :)
Answer:
D: 50 Square Units
Step-by-step explanation:
Step-by-step explanation:
The area of the triangular base is: 19
square units
How to calculate the base area
The given parameters are:
Volume = 27.36 cubic units
Height = 2.88 unit
The volume of a triangular prism is:
V = 0.5 * B *h
Where B represents the base area.
So, we have:
27.36 = 0.5 * B * 2.88
27.36 B * 1.44 -
Solve for B
B = 19
Hence, the area of the triangular base is: 19 square units
Answer:
7
Step-by-step explanation:
Remark
The two angles with x in their numerical value are added to get 108
Solution
10x + 2 + 4x + 8 = 108 Collect like terms
14x + 10 = 108 Subtract l0 from both sides.
14x + 10 -10 = 108 - 10 Collect like terms
14x = 98 Divide by 14
x = 98/14
x = 7
