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Gre4nikov [31]
3 years ago
14

Food A contains 150 calories in 3/4 of a serving. Food B contains 250 calories in 2/3 of a serving. Find each unit rate. Which f

ood has fewer calories per serving?
Mathematics
2 answers:
Gre4nikov [31]3 years ago
8 0

Answer:

Food A has fewer calories per serving so it wins.

Step-by-step explanation:

has fewer than B

Leviafan [203]3 years ago
5 0
The unit rate is going to be calories per serving....calories / serving

Food A :
150 / (3/4) =
150 * 4/3 =
600/3 =
200 calories per serving

Food B :
250 / (2/3) =
250 * 3/2 =
750/2 =
375 calories per serving

Therefore, Food A has fewer calories per serving <==
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If A and B are two rational numbers such that A<B

Then X = A + (B-A)/π would be an example of an irrational number

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in priyas math class there are 10 boys and 15 girls. What is the ratio of boys to girls in priyas math class? express your answe
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Answer:

2:3 , you divide by common denominator

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Step-by-step explanation:

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4 1/2 : 3 1/4 change into simplest form of ratio help fast please​
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Answer:

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Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
The equation p=100−5t represents the percent p of battery power remaining in a tablet after t hours.
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7 0
3 years ago
1. (10pts] Let A = {1, 2, 3, 4, 5}, let B = {1,4,5,7,8,9}, and let C = {2, 4, 6, 7,9}. Determine each of the following (a) An Bn
alisha [4.7K]

Answer and explanation:

Given : Let A = {1, 2, 3, 4, 5}, let B = {1,4,5,7,8,9}, and let C = {2, 4, 6, 7,9}.

To find : Determine each of the following,

a) (A\cap B)\cap C

b) (A\cup B)\cap (A\cup C)

c) A - (B\cup C)

d) (A-C) (C-A)

Solution :

The union of two sets is a new set that contains all of the elements that are in at least one of the two sets.

The intersection of two sets is a new set that contains all of the elements that are in both sets.

a) (A\cap B)\cap C

A\cap B=\{1,4,5\}

Then, (A\cap B)\cap C=\{4\}

b) (A\cup B)\cap (A\cup C)

A\cup B=\{1,2,3,4,5,7,8,9\}

A\cup C=\{1,2,3,4,5,7,9\}

(A\cup B)\cap (A\cup C)=\{1,2,3,4,5,7,9\}

c) A - (B\cup C)

B\cup C=\{1,2,4,5,6,7,8,9\}

A - (B\cup C)=\{3\}

d) (A-C) (C-A)

A-C=\{1,3,5\}

C-A=\{6,7,9\}

(A-C) (C-A)=\{1,3,5\}\times\{6,7,9\}

(A-C) (C-A)=\{(1,6),(1,7),(1,9),(3,6),(3,7),(3,9),(5,6),(5,7),(5,9)\}

5 0
3 years ago
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