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Shkiper50 [21]
3 years ago
6

What is the negative square root of 64/4?

Mathematics
1 answer:
Goryan [66]3 years ago
8 0

4/64

then that simplifies to 1/16

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A wheelchair ramp rises 1.5 feet for every 18 feet of horizontal distance it covers. Find the rate of change of the ramp
Ierofanga [76]
By definition the rate of change of a function is given by:
 AVR =  \frac{Change In Y}{Change In X}
 Or equivalently:
 AVR = \frac{y2 - y1}{x2 - x1}
 Substituting the values given in the problem we have:
 AVR = \frac{1.5}{18}
 Rewriting we have:
 AVR = 0.08
 Answer:
 
the rate of change of the ramp is:
 
AVR = 0.08
7 0
3 years ago
The population mean annual salary for environmental compliance specialists is about ​$63 comma 500. A random sample of 31 specia
Nat2105 [25]

Answer:

0.0035289

Step-by-step explanation:

From the question;

mean annual salary = $63,500

n = sample size = 31

Standard deviation = $6,200

Firstly, we calculate the z-score of $60,500

Mathematically;

z-score = x-mean/SD/√n = (60500-63500)/6200/√(31) = -2.6941

So we want to find the probability that P(z < -2.6941)

We can get this from the standard normal table

P( z < -2.6941) = 0.0035289

3 0
3 years ago
Write -6.1 as a mixed number in simplest form.
butalik [34]
-6.1=-(6+1/10)

-6 1/10
8 0
3 years ago
The 12th term in a sequence with a common difference of-9 is -106. which of the following formulas can be used to represent this
Effectus [21]

Answer:

T12=a-99=106

Step-by-step explanation:

that's the answer

6 0
2 years ago
If <img src="https://tex.z-dn.net/?f=%20300cm%5E%7B2%7D%20" id="TexFormula1" title=" 300cm^{2} " alt=" 300cm^{2} " align="absmid
Artist 52 [7]
Check the picture below.  Recall, is an open-top box, so, the top is not part of the surface area, of the 300 cm².  Also, recall, the base is a square, thus, length = width = x.

\bf \textit{volume of a rectangular prism}\\\\&#10;V=lwh\quad &#10;\begin{cases}&#10;l = length\\&#10;w=width\\&#10;h=height\\&#10;-----\\&#10;w=l=x&#10;\end{cases}\implies V=xxh\implies \boxed{V=x^2h}\\\\&#10;-------------------------------\\\\&#10;\textit{surface area}\\\\&#10;S=4xh+x^2\implies 300=4xh+x^2\implies \cfrac{300-x^2}{4x}=h&#10;\\\\\\&#10;\boxed{\cfrac{75}{x}-\cfrac{x}{4}=h}\\\\&#10;-------------------------------\\\\&#10;V=x^2\left( \cfrac{75}{x}-\cfrac{x}{4} \right)\implies V(x)=75x-\cfrac{1}{4}x^3

so.. that'd be the V(x) for such box, now, where is the maximum point at?

\bf V(x)=75x-\cfrac{1}{4}x^3\implies \cfrac{dV}{dx}=75-\cfrac{3}{4}x^2\implies 0=75-\cfrac{3}{4}x^2&#10;\\\\\\&#10;\cfrac{3}{4}x^2=75\implies 3x^2=300\implies x^2=\cfrac{300}{3}\implies x^2=100&#10;\\\\\\&#10;x=\pm10\impliedby \textit{is a length unit, so we can dismiss -10}\qquad \boxed{x=10}

now, let's check if it's a maximum point at 10, by doing a first-derivative test on it.  Check the second picture below.

so, the volume will then be at   \bf V(10)=75(10)-\cfrac{1}{4}(10)^3\implies V(10)=500 \ cm^3

6 0
3 years ago
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