The strongest indicator of variability in data sets with outliers or skewed distributions is the interquartile range. It's unlikely to be impacted by outliers because it's based on numbers that come from the centre half of the distribution.
Your data's spread from the lowest to the greatest value in the distribution is indicated by the range. The calculation of this variability index is the simplest.
If your distribution doesn't contain any extreme values, the range is typically a decent indicator of variability. The range can provide information about the breadth of the distribution when combined with metrics of central tendency. But if your data collection contains outliers, the range may be deceptive.
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Answer:
Step-by-step explanation:
Given
Ferret:
Labrador Retriever
Required
Determine the slope
Represent the given as x or y
Taking the weight as explanatory variable;
We have:
x = 2.1; y = 3.4
x = 7.5; y = 70
Slope is calculated as:
<em>Hence, the slope is 12.33</em>
Answer:
The answer is option D.
Step-by-step explanation:
First we must first find the LCM
the LCM of x² - 9 and x + 3 is x² - 9
So we have
Hope this helps you
The answer would be 17/18 in lowest terms.
The square root of 16 is 4 you do 4x4=16
