By the divergence theorem, the surface integral over
is
where
denotes the space bounded by
. Assuming the vector field is given to be
then
Converting to spherical coordinates, we take
so that the triple integral becomes
Now the integral over
alone will be the difference of the integral over
and the integral over
, i.e.
We can parameterize the points in
by
so that the integral over
is
So, the integral over
alone evaluates to
Solution:
Standard Error Formula:
SEx̄ = S / UNDERROOT N
where,
SEx̄ = Standard Error of the Mean
s = Standard Deviation of the Mean
n = Number of Observations of the Sample
SExĚ„ = 51.60/ âš21 = 11.26004314
So, standard error = 11.26004314
Fred walked 10 meters down and 24 to the right. You can think of these two segments as the legs of a right triangle.
The hypotenuse of this triangle is the path Fred would have walked through the pond. So, this distance is
So, instead of walking 10+24=34 meters, he could have walked 26 meters, saving 34-26=8 meters.
Answer:
A. g(x)=9(3^(x−2))
Step-by-step explanation:
g(x) = 3^x = 3^(x-2+2) = (3^2)(3^(x-2))
g(x) = 9(3^(x-2)) . . . . . matches choice A