3y^2/9y^4 state restrictions and simplify
1 answer:
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Ok
y=-0.04x^2+8.3x+4.3
when the rocket reaches the ground (when height=0, ie when y=0), then the rocket will land, find the x coordinate
set y=0
0=-0.04x^2+8.3x+4.3
use quadratic formula
if you have ax^2+bx+c=0, then
x=
a=-0.04
b=8.3
c=4.3
x=
x=208.017 or -0.516785
xrepresents horizontal distance
you cannot have a negative horizontal distance unless you fired and theh wind blew it backwards
therefor x=280.017 is the answer
208.02 m
y=-0.04x^2+8.3x+4.3
when the rocket reaches the ground (when height=0, ie when y=0), then the rocket will land, find the x coordinate
set y=0
0=-0.04x^2+8.3x+4.3
use quadratic formula
if you have ax^2+bx+c=0, then
x=
a=-0.04
b=8.3
c=4.3
x=
x=208.017 or -0.516785
xrepresents horizontal distance
you cannot have a negative horizontal distance unless you fired and theh wind blew it backwards
therefor x=280.017 is the answer
208.02 m
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Hi my lil bunny!
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Let's solve your equation step-by-step.
Step 1: Simplify both sides of the equation.
(Combine Like Terms)
Step 2: Subtract 5 from both sides.
Step 3: Divide both sides by -1.
Answer :
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Have a great day/night!
❀*May*❀