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ArbitrLikvidat [17]
3 years ago
10

Identify the null and alternative hypotheses, test statistic, critical value(s) or P-value (or range of P-values) as appropriate

, and state the final conclusion that addresses the original claim. A cereal company claims that the mean weight of the cereal in its packets is 14 oz. The weights (in ounces) of the cereal in a random sample of 8 of its cereal packets are listed below. 14.6 13.8 14.1 13.7 14.0 14.4 13.6 14.2 Test the claim at the 0.01 significance level.H0: μ = 14 oz. H1: μ 14 oz. Test statistic: t = 0.408 Critical values: t = ±3.499. Fail to reject H0. There is not sufficient evidence to warrant rejection of the claim that the mean weight is 14 ounces.Assume that you plan to use a significance level of α = 0.05 to test the claim that p1 = p2, Use the given sample sizes and numbers of successes to find the pooled estimate p. n1 = 100 n2 = 100 x1 = 33 x2 = 36 A) 0.241 B) 0.380 C) 0.310 D) 0.345
Mathematics
1 answer:
Kobotan [32]3 years ago
6 0

Answer:

Step-by-step explanation:

Given that  A cereal company claims that the mean weight of the cereal in its packets is 14 oz

Test the claim at the 0.01 significance level.H0: μ = 14 oz. H1: μ 14 oz.

Parameter  Value

Mean  14.050

SD  0.346

SEM  0.122

N  8      

90% CI  13.818 to 14.282

95% CI  13.760 to 14.340

99% CI  13.621 to 14.479

Minimum  13.6

Median  14.05

Maximum  14.6

Test statistic: t = 0.408

Critical values: t = ±3.499.

Since test statistic falls within the critical values, we accept the null hypothesis at 1% significance.

Fail to reject H0. There is not sufficient evidence to warrant rejection of the claim that the mean weight is 14 ounces.

Assume that you plan to use a significance level of α = 0.05 to test the claim that p1 = p2, Use the given sample sizes and numbers of successes to find the pooled estimate p. n1 = 100 n2 = 100 x1 = 33 x2 = 36

proportion difference = 0.03

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THIS IS THE COMPLETE QUESTION BELOW;

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