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Paraphin [41]
4 years ago
10

Please help me i really need it i beg of u

Mathematics
1 answer:
Gnom [1K]4 years ago
8 0

Answer:

6) B. Reflection over the y-axis, then reflection over the x-axis

7) B. The initial value of the function is the y-intercept of the line, 275

8) A. y = 45 - 6x

Step-by-step explanation:

6) See first attached file :)

7) Option A is incorrect because the rate of change/slope is "-20x" not just "-20." Option C is incorrect because the initial value/y-intercept is $275 and not $2. Option D is incorrect because it implies she doesn't withdraw $20 the first month, which wasn't mentioned in the question. Option B is the only one to apply to the graph. See second attached file for graph reference.

8) The question explains the function "y=6x+45" and that matches all options except for option A.

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Find the slope of the line that passes through the points A (3, -1), B (3,5) *
Harman [31]

Answer:

0 or infinity i believe

Step-by-step explanation:

slope equation is rise over run or y2-y1 over x2 - x1, so 5 - (-1) turns into 5+1 because of the double negative so that equals six. then 3-3 is 0 so it would be 6 over zero and by dividing that'd equal zero aka infinity for slope

3 0
3 years ago
Consider the line y=4/3x + 3
svet-max [94.6K]

Answer:

Step-by-step explanation:

Consider the line y=4/3x + 3

-

Find the equation of the line that is perpendicular to this line and passes through the point (-9, -5)

Find the equation of the line that is parallel to this line and passes through the point (-9, -5).

6 0
2 years ago
Which angle is in standard position
Readme [11.4K]

Answer:

The bottom one

Step-by-step explanation:

its vertex is located at the origin and one ray is on the positive x-axis

4 0
4 years ago
Read 2 more answers
What is an equation of the line that passes through the points (-2, -5)and (-1, 1)?
suter [353]
First find the slope(m)



Slope= y2-y1/x2-x1= (1-(-5))/(-1-(-2))= 6/1 = 6

Then find the y intercept (move up six and right one from (-1, 1) to get (0, 7)

The y-intercept is y=7

Now make the equation

Y= slope(x) + y-intercept

Y=6x+7
5 0
4 years ago
Read 2 more answers
A uniform 41.0 kg scaffold of length 6.6 m is supported by two light cables, as shown below. A 74.0 kg painter stands 1.0 m from
Nimfa-mama [501]

Step-by-step explanation:

Let

m_p = mass of the painter

m_s = mass of the scaffold

m_e = mass of the equipment

T = tension in the cables

In order for this scaffold to remain in equilibrium, the net force and torque on it must be zero. The net force acting on the scaffold can be written as

3T = (m_p + m_s + m_e)g\:\:\:\:\:\:\:(1)

Set this aside and let's look at the net torque on the scaffold. Assume the counterclockwise direction to be the positive direction for the rotation. The pivot point is chosen so that one of the unknown quantities is eliminated. Let's choose our pivot point to be the location of m_e. The net torque on the scaffold is then

T(1.4\:\text{m}) + m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m}) - 2T(5.2\:\text{m}) = 0

Solving for T,

9T = m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m})

or

T = \frac{1}{9}[m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m})]

\:\:\:\:= 423.3\:\text{N}

To solve for the the mass of the equipment m_e, use the value for T into Eqn(1):

m_e = \dfrac{3T - (m_p + m_s)g}{g} = 14.6\:\text{kg}

6 0
3 years ago
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