The answer: [B]: h = 2A / (b1 + b2) .
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Explanation:
Given: A = (½) * (b1 + b2) * h ;
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→Multiply EACH side of the equation by "2", to get rid of the fraction, "<span>½";
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→ 2*A = 2 * (½) * (b1 + b2) * h ;
→ 2* A = 1 * (b1 + b2) * h ;
→ 2A = (b1 + b2) * h ;
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→ Now, divide EACH side of the equation by: "(b1 + b2)" ; to isolate "h" on one side of the equation;
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→ 2A / (b1 + b2) = [(b1 + b2) * h] / (b1 + b2) ;
→ 2A / (b1 + b2) = h ; ↔ h = 2A / (b1 + b2) ; which corresponds to:
"Answer choice: [B]" .
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Answer:
The third one
Step-by-step explanation:
IF THIS GETS TAKEN DOWN IMA SCREAM
Answer:
Amount of hay in first barn = 90 tons
Amount of hay in second barn song = 30 tons
Step-by-step explanation:
Let the amount of hay in second barn be x, then hay in first barn will be 3x.
20 tons of hay was removed from first barn and ws added to second barn.
Now, the amount of hay in first barn = 3x -20
Amount of hay in second barn = x+20
The equation now formed is:
x+20 =
(3x-20)
7x+14 = 15x -100
-8x = -240
8x = 240
x = 30
3x = 90
Amount of hay in first barn = 90 tons
Amount of hay in second barn song = 30 tons