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kow [346]
3 years ago
11

-3/2×-2=-1/4×+3 what is the answer?

Mathematics
1 answer:
kykrilka [37]3 years ago
5 0

Answer:

x= -4

Step-by-step explanation:

hope this helped :)

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I’m stuck please help
weqwewe [10]
Since there are 2 negatives in front of the 8, it becomes positive 8

-4q + 8q + 10

4q + 10

4q = -10

q = -10/4 or reduce it to -5/2
4 0
3 years ago
Read 2 more answers
In how many ways can we seat 3 pairs of siblings in a row of 7 chairs, so that nobody sits next to their sibling
monitta

Answer:

1,968

Step-by-step explanation:

Let x₁ and x₂, y₁ and y₂, and z₁ and z₂ represent the 3 pairs of siblings, and let;

Set X represent the set where the siblings x₁ and x₂ sit together

Set Y represent the set where the siblings y₁ and y₂ sit together

Set Z represent the set where the siblings z₁ and z₂ sit together

We have;

Where the three siblings don't sit together given as X^c∩Y^c∩Z^c

By set theory, we have;

\left | X^c \cap Y^c \cap Z^c  \right | = \left | X^c \cup Y^c \cup Z^c  \right | =  \left | U  \right | - \left | X \cup Y \cup Z  \right |

\left | U  \right | - \left | X \cup Y \cup Z  \right | = \left | U  \right | - \left (\left | X \right | +  \left | Y\right | +  \left | Z\right | -  \left | X \cap Y\right | -  \left | X \cap Z\right | -  \left | Y\cap Z\right | +  \left | X \cap Y \cap Z\right | \right)

Therefore;

\left | X^c \cap Y^c \cap Z^c  \right | = \left | U  \right | - \left (\left | X \right | +  \left | Y\right | +  \left | Z\right | -  \left | X \cap Y\right | -  \left | X \cap Z\right | -  \left | Y\cap Z\right | +  \left | X \cap Y \cap Z\right | \right)

Where;

\left | U\right | = The number of ways the 3 pairs of siblings can sit on the 7 chairs = 7!

\left | X\right | = The number of ways x₁ and x₂ can sit together on the 7 chairs = 2 × 6!

\left | Y\right | = The number of ways y₁ and y₂ can sit together on the 7 chairs = 2 × 6!

\left | Z\right | = The number of ways z₁ and z₂ can sit together on the 7 chairs = 2 × 6!

\left | X \cap Y\right | = The number of ways x₁ and x₂ and y₁ and y₂ can sit together on the 7 chairs = 2 × 2 × 5!

\left | X \cap Z\right | = The number of ways x₁ and x₂ and z₁ and z₂ can sit together on the 7 chairs = 2 × 2 × 5!

\left | Y \cap Z\right | = The number of ways y₁ and y₂ and z₁ and z₂ can sit together on the 7 chairs = 2 × 2 × 5!

\left | X \cap Y \cap Z\right | = The number of ways x₁ and x₂,  y₁ and y₂ and z₁ and z₂ can sit together on the 7 chairs = 2 × 2 × 2 × 4!

Therefore, we get;

\left | X^c \cap Y^c \cap Z^c  \right | = 7! - (2×6! + 2×6! + 2×6! - 2 × 2 × 5! - 2 × 2 × 5! - 2 × 2 × 5! + 2 × 2 × 2 × 4!)

\left | X^c \cap Y^c \cap Z^c  \right | = 5,040 - 3072 = 1,968

The number of ways where the three siblings don't sit together given as \left | X^c \cap Y^c \cap Z^c  \right |  = 1,968

5 0
3 years ago
What is the value of x if 2x - 7 = 103 x=__________
Greeley [361]

Answer:

x=55

Step-by-step explanation:

2x-7=103

2x=103+7

2x=110

x=55

5 0
2 years ago
Read 2 more answers
First term is is 22 and the common difference is -13
bonufazy [111]

Answer:

a_{n} = 35 - 13n

Step-by-step explanation:

Assuming you require the n th term formula

The n th term of an arithmetic sequence is

a_{n} = a₁ + (n- 1)d

where a₁ is the first term and d the common difference

Here a₁ = 22 and d = - 13, thus

a_{n} = 22 - 13(n - 1) = 22 - 13n + 13 = 35 - 13n

8 0
3 years ago
3.27x+1.28y+1.83x−2.77y
Firdavs [7]

Answer:

5.1x - 1.49y

Step-by-step explanation:

We need to add or substract like terms.

like terms are the terms that have the same variable, in this case:

3.27x and 1.83x are like terms, and adding them we get:

3.27x + 1.83x = 5.1x (you add only the coefficients and the x stays the same)

we do the same for the terms with 'y':

1.28y and −2.77y are like terms, but in this case we must substract because of the − sign:

1.28y −2.77y = -1.49y

the final answer is the conjunction of the two results that we obtained:

5.1x - 1.49y

8 0
2 years ago
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