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2 years ago

Please help me with this geometry question. i attached an image.

Mathematics

1 answer:

Tju [1.3M]2 years ago

7 0

If BE is perpendicular to DF,that means that angle DEB is 90 degrees. Since we know that DEA is 71 degrees, subtract 90 to 71 to find the value for angle AEB. 90-71 equals 19 so angle AEBis 19 degrees.

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Recall the equation that modeled the volume of the raised flower bed, y, in terms of the width of the box, y = x3 + 11x2 − 312x.

lakkis [162]

Answer:

48 cubic feet of mulch

Step-by-step explanation:

12 feet long x 4 feet wide x 1 foot deep of mulch= 48 cubic feet of mulch

8 0

2 years ago

A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. (a) Describe the

Ivanshal [37]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

b) $z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

c) $z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

d) $z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 83, \sigma = 27$

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

Part b

We want this probability:

$P(\bar X>89)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89 we got:

$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

$z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

Part d

We want this probability:

$P(79.4 < \bar X < 89.3)$

We find the z scores:

$z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

8 0

3 years ago

A line segment has (three one two zero) endpoints

Masja [62]

A line segment has (three one two zero) endpoints

The answer is 2

4 0

3 years ago

Read 2 more answers

How do i solve this problem

mamaluj [8]

As they are similar corresponding sides are in the same ratio, so

18/15 = x / 4

x = 4*18 / 15
x = 4.8 answer

7 0

2 years ago

At the beginning of the fall, the water level of a lake is 12

spayn [35]

x = normal water level

x - 12 - 13 = x - 25

so it is 25 feet below the normal water level

6 0

3 years ago