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hram777 [196]
3 years ago
15

Please help me with this geometry question. i attached an image.

Mathematics
1 answer:
Tju [1.3M]3 years ago
7 0
If BE is perpendicular to DF,that means that angle DEB is 90 degrees. Since we know that DEA is 71 degrees, subtract 90 to 71 to find the value for angle AEB. 90-71 equals 19 so angle AEBis 19 degrees.
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Which relation does not represent a function? A) a vertical line B) y = 5 9 x - 3 C) a horizontal line D) {(1, 7), (3,7), (5, 7)
Alisiya [41]

Answer:

A) a vertical line does not represent a function.

Step-by-step explanation:

For a relation to be a function for each value of x there must be only one value of y. In other words a function is one in which each value in the domain set corresponds to only one value in the range set.

Let us check for this condition in the give choices:

A) a vertical line

A vertical line is given as x=a which meas it is parallel to y-axis and has infinite number of y values for a single x value.

So, its Not a function

B) y=\frac{5}{9}x-3

For the given equation, on plugging in some x value will give a single y value.

So, its a Function

C) a horizontal line

A horizontal line is given as y=a which meas it is parallel to x-axis and has infinite number of x values giving a single y value.

So, its a Function

D) {(1, 7), (3,7), (5, 7), (7,7)}

For the given set for different x valuesthere is only one y value.

So, its a Function

4 0
3 years ago
Read 2 more answers
16. Solve this inequality: 3p - 16 < 20.
tamaranim1 [39]

Answer:

Answer is p < 12

Hope this helps

8 0
3 years ago
Help pls I'll mark brainliest
attashe74 [19]

Answer:

-3/8

sqrt(73) or 8.54

Step-by-step explanation:

6 0
3 years ago
Is the graph a linear function, nonlinear function, or relation?
alexdok [17]

Answer:

yes its linear

Step-by-step explanation:

bc

7 0
3 years ago
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Simplify the expression and solve the equation. Show all calculations
melamori03 [73]

 

\displaystyle\bf\\\sqrt{5p+5}=\sqrt{6p+3}\\\\ 5p+5=6p+3\\\\5p-6p=3-5\\\\-p=-2~\Big|\times(-1)\\\\\boxed{\bf p=2}\\\\\text{Verify:}\\\\\sqrt{5\times2+5}=\sqrt{6\times2+3}\\\\\sqrt{10+5}=\sqrt{12+3}\\\\\sqrt{15}=\sqrt{15}~~~~OK!

.

4 0
4 years ago
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