Let 
be the speed of train A, and let's set the origin in the initial position of train A. The equations of motion are
where 
are the positions of trains A and B respectively, and t is the time in hours.
The two trains meet if and only if 
, and we know that this happens after two hours, i.e. at 
Solving this equation for v we have
So, train A is travelling at 105 km/h. This implies that train B travels at
The answer to this query is AA similarity postulate. <span>
<span>Because the triangles given are only similar in angle but
dissimilar in sides which makes it incongruent with respect to the sides, AA
similarity postulate is the exact answer.
SAS ASA are not possible answers. </span></span>
B (2x+5y=-10) is the answer.
8/15 is about 0.53
It would be closer to 1/2 or 1 over 2
Answer:
<h2>4</h2><h2>11</h2>
Step-by-step explanation:
20:5=4 (minutes for 1 meter)
4*11=44 minutes for 11 meters
or
20 : 5 = x : 11
x = 20*11:5
x = 44
or
20:5* 11=44
