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iogann1982 [59]
3 years ago
7

I just need you to answer 4 questions for me...

Mathematics
1 answer:
dexar [7]3 years ago
8 0

1. 6(2y + 1)

2.  4(4k+6)

3. 4r

4. 18x+24



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Two passenger train, A and B, 450 km apart, star to move toward each other at the same time and meet after 2hours.
likoan [24]

Let v be the speed of train A, and let's set the origin in the initial position of train A. The equations of motion are

\begin{cases}s_A(t) = vt\\s_B(t) = -\dfrac{8}{7}vt+450\end{cases}

where s_A,\ s_B are the positions of trains A and B respectively, and t is the time in hours.

The two trains meet if and only if s_A=s_B, and we know that this happens after two hours, i.e. at t=2

\begin{cases}s_A(2) = 2v\\s_B(2) = -\dfrac{16}{7}v+450\end{cases}\implies 2v = -\dfrac{16}{7}v+450

Solving this equation for v we have

2v = -\dfrac{16}{7}v+450 \iff \dfrac{30}{7}v=450 \iff v=\dfrac{450\cdot 7}{30} = 105

So, train A is travelling at 105 km/h. This implies that train B travels at

105\cdot \dfrac{8}{7} = 15\cdot 8=120 \text{ km/h}

5 0
3 years ago
Which postulate or theorem could be used to prove triangleLMQ is congruent to triangleLNP
Sliva [168]

The answer to this query is AA similarity postulate. <span>

<span>Because the triangles given are only similar in angle but dissimilar in sides which makes it incongruent with respect to the sides, AA similarity postulate is the exact answer. 

SAS ASA are not possible answers. </span></span>

6 0
3 years ago
Read 2 more answers
Please, help im being timed !!!
Agata [3.3K]
B (2x+5y=-10) is the answer.
3 0
3 years ago
8 over 15? is it closer to 0, 1 over 2 or 1
ruslelena [56]
8/15 is about 0.53
It would be closer to 1/2 or 1 over 2
4 0
3 years ago
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A snail travels 5 meters in 20 minutes. He travels the same amount of time per meter. How long will it take him to travel 11 met
Llana [10]

Answer:

<h2>4</h2><h2>11</h2>

Step-by-step explanation:

20:5=4 (minutes for 1 meter)

4*11=44 minutes for 11 meters

or

20 : 5 = x : 11

x = 20*11:5

x = 44

or

20:5* 11=44

7 0
3 years ago
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