3 years ago

How many different ways can you solve 73*15

1 answer:

Vinil7 [7]3 years ago

4 0

You can solve it my adding multiplying subtracting and dividing each one helps you

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Step-by-step explanation:

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Bas_tet [7]

2x(5y). -4 1 4

The coefficient is 414

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Monica [59]

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9966 [12]

Answer:

In the comments of the post

To be short, A is the answer

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3 years ago

andreyandreev [35.5K]

Answer:

Option D) $-2y(2y^4-3y^2-4y+1)$ is correct

Therefore $-4y^5+6y^3+8y^2-2y=-2y(2y^4-3y^2-4y+1)$

Step-by-step explanation:

Given polynomial is $-4y^5+6y^3+8y^2-2y$

To factorise the given polynomial by taking out the common terms of the given polynomial :

$-4y^5+6y^3+8y^2-2y$
$=2y(-2y^4+3y^2+4y-1)$ ( here 2y is GCF common term so taking outside the terms of the polynomial )
$=-2y(2y^4-3y^2-4y+1)$ ( now taking (-) outside )

Therefore $-4y^5+6y^3+8y^2-2y=-2y(2y^4-3y^2-4y+1)$

Option D) $-2y(2y^4-3y^2-4y+1)$ is correct

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4 years ago