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Rina8888 [55]
3 years ago
5

Suppose the heights of a population of people are normally distributed with a mean of 65.5 inches and a standard deviation of 2.

6 inches. a. Find the probability that a randomly selected person from this population is between 64.2 and 67.2 inches tall. (5 points) b. What height separates the bottom 95% of data from the top 5%? (5 points)

Mathematics
1 answer:
kupik [55]3 years ago
5 0

Answer:

a) P(64.2

b) 69.764

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

2) Part a

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(65.5,2.6)

Where \mu=65.5 and \sigma=2.6

We are interested on this probability

P(64.2

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(64.2

And we can find this probability on this way:

P(-0.50

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.

P(-0.50

3) Part b

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.05   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.95 of the area on the left and 0.05 of the area on the right it's z=1.64. On this case P(Z<1.64)=0.95 and P(z>1.64)=0.05

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.64

And if we solve for a we got

a=65.5 +1.64*2.6=69.764

So the value of height that separates the bottom 95% of data from the top 5% is 69.764.

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Geometry! Please help!!
krek1111 [17]
Problem One
Find AM
AM = 71.5 - 22 = 49.5

Step Two
State the Givens.
AM = 49.5
MN = 71.5
MB = x
MP = 97.5

Step Three
Set up the Proportion

AM : NM :: x : PM
49.5 : 71.5 :: x : 97.5

Substitute and solve
49.5 / 71.5 = x / 97.5    Cross Multiply
49.5 * 97.5 = 71.5 * x   Combine the numbers on the left.
4860.375 = 71.5 * x     Divide by 71.5
4860.375 / 71.5 = x      
x = 67.98

Problem Two
Remark
This is just a straight application of the Pythagorean Theorem
a^2 + b^2 = c^2
a = 10
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c = ??

10^2 + 24^2 = c^2
100 + 576 = c^2
676 = c^2
sqrt(c^2) = sqrt(676)
c = 26  <<<< answer
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<em>option</em><em> </em><em>C</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>option</em><em>.</em>

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<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em>

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