Answer:
<h2>A. (0,1)</h2>
Step-by-step explanation:
The question lacks the e=required option. Find the complete question below with options.
Which of the following points does not belong to the quadratic function
f(x) = 1-x²?
a.(0,1) b.(1,0) c.(-1,0)
Let f(x) = 0
The equation becomes 1-x² = 0
Solving 1-x² = 0 for x;
subtract 1 from both sides;
1-x²-1 = 0-1
-x² = -1
multiply both sides by minus sign
-(-x²) = -(-1)
x² = 1
take square root of both sides;
√x² = ±√1
x = ±1
x = 1 and x = -1
when x = 1
f(x) = y = 1-1²
y = 1-1
y = 0
when x = -1
f(x) = y = 1-(-1)²
y = 1-1
y = 0
Hence the coordinate of the function f(x) = 1-x² are (±1, 0) i.e (1, 0) and (-1, 0). The point that does not belong to the quadratic function is (0, 1)
Answer:
a=1 or a=5
Step-by-step explanation:
+4=6a−1
Step 1: Subtract 6a-1 from both sides.
+4−(6a−1)=6a−1−(6a−1)
−6a+5=0
Step 2: Factor left side of equation.
(a−1)(a−5)=0
Step 3: Set factors equal to 0.
a−1=0 or a−5=0
a=1 or a=5
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Answer:
7
Step-by-step explanation:
Working backwards:
19 + 9 = 28
28/ 4 = 7
Checking work:
7 x 4 = 28
28 - 9 = 19
Well, bearing in mind that, a year has 12 months, so 18 months is really just 18/12 of a year, or 3/2 a year, then
Answer:
14
Step-by-step explanation:
3*10=30
5*14=70
30+70=100!!!
