2x - y = 5
x + 3y = 7
I'm assuming you mean the coefficient matrix.
![\left[\begin{array}{ccc}2&-1\\1&3\end{array}\right] =(2)(3)-(-1)(1)=6+1=7](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26-1%5C%5C1%263%5Cend%7Barray%7D%5Cright%5D%20%3D%282%29%283%29-%28-1%29%281%29%3D6%2B1%3D7)
x + 3y = 7
I'm assuming you mean the coefficient matrix.
IF THIS WRONG I FAIL!!!!
1 answer:
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ANSWER TO QUESTION 1
The given function is
The partial derivative of f with respect to x means we are treating y as a constant. The first derivative is
and the second derivative with respect to x is,
ANSWER TO QUESTION 2
The given function is
The partial derivative of f with respect to y means we are treating x as a constant. The first derivative is
and the second derivative with respect to y is
ANSWER TO QUESTION 3
Our first mixed partial is
We need to differentiate
again. But this time with respect to y.
Since this is a product of two functions of y, we apply the product rule of differentiation to obtain,
ANSWER TO QUESTION 4
The second mixed partial is
We need to differentiate
again. But this time with respect to x.
Since this is a product of two functions of x, we apply the product rule of differentiation to obtain,
Hence,
The given function is
The partial derivative of f with respect to x means we are treating y as a constant. The first derivative is
and the second derivative with respect to x is,
ANSWER TO QUESTION 2
The given function is
The partial derivative of f with respect to y means we are treating x as a constant. The first derivative is
and the second derivative with respect to y is
ANSWER TO QUESTION 3
Our first mixed partial is
We need to differentiate
again. But this time with respect to y.
Since this is a product of two functions of y, we apply the product rule of differentiation to obtain,
ANSWER TO QUESTION 4
The second mixed partial is
We need to differentiate
again. But this time with respect to x.
Since this is a product of two functions of x, we apply the product rule of differentiation to obtain,
Hence,