A: is the answer that the one u click
Answer:
4
Step-by-step explanation:
AB = ![\sqrt{[(4-(-4)]^{2} - [1-(-3)]^{2} }](https://tex.z-dn.net/?f=%5Csqrt%7B%5B%284-%28-4%29%5D%5E%7B2%7D%20-%20%5B1-%28-3%29%5D%5E%7B2%7D%20%7D)
= 4
Step-by-step explanation:
the angle ABC = 180 - x, as ABD and ABC are complementary angles on top of the bottom line : all angles around a point on one side of a line are always adding up to 180 degrees.
but because we also know that the sum of all angles in a triangle is 180 degrees too, we can say
180 = ACB + ABC + CAB
180 = y + 180 - x + CAB
0 = y - x + CAB
x = y + CAB
x - y = CAB
therefore, the second answer option is correct.
Answer:
--- 1 over 5 squared
Step-by-step explanation:
When multiplying terms with a common base, you just add the exponents:
That's true even when you don't have any exponents.
A negative exponent isn't fully simplified, so there's another rule to use:
That is '1 over x to the y' if it's too small to read.
Some basic formulas involving triangles
\ a^2 = b^2 + c^2 - 2bc \textrm{ cos } \alphaa 2 =b 2+2 + c 2
−2bc cos α
\ b^2 = a^2 + c^2 - 2ac \textrm{ cos } \betab 2=
m_b^2 = \frac{1}{4}( 2a^2 + 2c^2 - b^2 )m b2 = 41(2a 2 + 2c 2-b 2)
b
Bisector formulas
\ \frac{a}{b} = \frac{m}{n} ba =nm
\ l^2 = ab - mnl 2=ab-mm
A = \frac{1}{2}a\cdot b = \frac{1}{2}c\cdot hA=
\ A = \sqrt{p(p - a)(p - b)(p - c)}A=
p(p−a)(p−b)(p−c)
\iits whatever A = prA=pr with r we denote the radius of the triangle inscribed circle
\ A = \frac{abc}{4R}A=
4R
abc
- R is the radius of the prescribed circle
\ A = \sqrt{p(p - a)(p - b)(p - c)}A=
p(p−a)(p−b)(p−c)
