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Answer:
Average size of the lots = ⅓ acre
Step-by-step explanation:
The question incomplete without specifying what we are to determine.
Question:A builder is buying property where she can build new houses. The line plot shows the sizes for each house. 1/6 has 6 X's 1/3 has 3 X's and 1/2 has 6 X's. Organize the information in a line plot. What is the average size of the lots? _________ acre
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Solution:
We are asked to organize the information in a line plot. See attachment for the line plot.
Given: 1/6 has 6 X's 1/3 has 3 X's and 1/2 has 6 X'sIn no particular order, the sizes of the lots are:1/6, 1/6, 1/6, 1/6, 1/6, 1/6, 1/3, 1/3, 1/3, 1/2, 1/2, 1/2, 1/2, 1/2 and 1/2 acre.
Let's count the number of lot for each size given.
For 1/6: there are 6 X's on the line plot of 1/6 number of lot for 1/6
= the lot × number of times it occurs
= (1/6) × 6 = 6/6 = 1 acre
For 1/3: there are 3 X's on the line plot of 1/3 number of lot for 1/3 = the lot × number of times it occurs
= (1/3) × 3 = 3/3 = 1 acre
For 1/2: there are 6 X's on the line plot of 1/2 number of lot for 1/2
= the lot × number of times it occurs
= (1/2) × 6 = 6/2= 3 acres
To find average size of the lots, we would sum all lot for each given size then divide by the total number of lots given.Sum of all lot for each given size = 1+1+3
Sum of all lot for each given size = 5
The total number of lots given = 15
Average size of the lots = 5/15 = 1/3
Average size of the lots = ⅓ acre
To find the critical points, first we derivate the function:
dy/dx has roots x = 0 and x = -5/6.
When x < -5/6, we can check that dy/dx is negative. When -5/6 < x < 0, we can check that dy/dx is positive. And, when x > 0, we can check that dy/dx is also positive.
Therefore, y is increasing when x > -5/6 and decrasing when x < -5/6. y has inflection points at x = -5/6 and x = 0