1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Harrizon [31]
3 years ago
15

Find the value of x that would prove this is an isosceles trapezoid. Then find each segment length.

Mathematics
1 answer:
vredina [299]3 years ago
4 0

Answer:

Check pdf

Step-by-step explanation:

Download pdf
You might be interested in
A French restaurant used 848,540 ounces of cream last year. This year, due to a menu update, it used 40% less. How much cream di
Vsevolod [243]

Answer:

339416

Step-by-step explanation:

848,540 * 40/100 = 339416

4 0
3 years ago
Pls pls help asap pls​
Rom4ik [11]

Answer is 1, my mobile is not good but

8 0
3 years ago
The slope-intercept form of a linear equation is y = mx + b, where x and y are coordinates of an ordered pair, m is the slope of
Savatey [412]

Divide both sides by x + b to get m by itself. The equation will look like this: m = \frac{y}{x+b}

5 0
3 years ago
Read 2 more answers
HI can you help me with this problem?The quantity demanded x for a certain brand of MP3 players is 300 units when the unit price
Vlad [161]

The demand equation is P = -0.05x + 105

STEP - BY - STEP EXPLANATION

What to find?

<em>The demand equation.</em>

The following information is used to solve the problem.

If (x₁ , y₁) and (x₂, y₂) are any dinstinct points on a line a non-vertical line L, then the equation of the line that has a slope(m) and passes through the point (x₁ , y₁) is given by the formula below:

y-y_1=_{}\frac{y_2-y_1}{x_2-x_1}(x-x_1)

Assume p, be the unit price and x be the demand when the price is $p.

From the question given, when the unit price x = 300 units, the demand p = $90 and when the unit price x = 1300 units, the demand p = $40

This means the demand curve passes through the points (300, 90) and (1300, 40).

Assume the demand equation is linear, then the line of the equation passes through the points (300, 90) and (1300, 40).

Now;

y=p x₁ =300 y₁ = 90 x₂ = 1300 y₂=40

Substitute the values into the function and simplify.

p-90=\frac{40-90}{1300-300}(x-300)

Simplify the above.

p-90=\frac{-50}{1000}(x-300)p-90=-0.05(x-300)

Open the parenthesis.

P- 90 = -0.05x + 15

Add 90 to both-side of the equation.

P = -0.05x + 15 + 90

P = -0.05x + 105

Hence, the demand function is P = -0.05x + 105

6 0
1 year ago
Solve the system of equations x+4y=15 2x-y=-15
Lady_Fox [76]

x+4y=15 2x-y=-15


We have to make x neg.


-2(x) + 4y (-2)= -2(15)


-2x-8y=-30

2x-y=-15


-9y= -45


Solve for y


Y=-45/-9


Y = 5

Substitute your y answer into one original equation to find x .


x+4y=15


X+4(5)=15


X+20=15


X=15-20


X= -5


Answer is (-5,5)

7 0
4 years ago
Other questions:
  • True or false to graph data points together you need to use a coordinate plane
    15·1 answer
  • Hypothesis testing on samples with fewer than 30 participants can be carried out by using the t-value for the corresponding leve
    12·1 answer
  • A map of Australia has a scale of 1cm : 110 km. If the distance between Darwin and Alice springs is 1444 kilometers, how far apa
    9·1 answer
  • If parallelogram ABCD was reflected over the y-axis, reflected over the x-axis,and rotated 180°, where would point A' lie?
    5·2 answers
  • The parent function y = 0.5x is blank across its domain because its base, b, is such that blank
    13·2 answers
  • Bob is having a party and wants to order some cakes.
    6·2 answers
  • This is worth 30points if u show work u will get brainliest
    12·2 answers
  • How math is calculated in our everyday life?​
    15·2 answers
  • –4x-2y=-2<br> x-2y=9<br> what do you get if you subtract the second from the first
    5·1 answer
  • IS THERE ANYONE THAT WILL HELP WITH THIS PROBLEM AND BRAINLLEST FOR CORRECT PEOPLE
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!