<h2><u>My </u><u>Answer</u><u> </u></h2>
<h2>
My Explanation</h2>
Although caffeine (a stimulant found in coffee and tea) is a relatively complicated molecule, it's only eight atoms of carbon, ten of hydrogen, four of nitrogen and two of oxygen – C8H10N4O2. This kind of representation is called a molecular formula – it tells us what kind of atoms we have, and how many of each.
<h2>#CarryOnLearning</h2>
<span>You can work out the following:
Mass = Density x Volume
Density = Mass Ă· Volume
Volume = Mass Ă· Density
The density of gold is 0.670205 oz/cm^3
The volume is length x width x depth = 7*3*2 = 42
The answer is Mass = 0.670205 x 42 = 281 ounces</span>
Answer:
Explanation:
Mixing Ammonia gas into a solution of Copper(II) Sulfate will give Ammonium Sulfate and a precipitate of Copper(II) Hydroxide (Cu(OH)₂). The Ksp of Cu(OH)₂ is published => 2.2 x 10⁻²². Such gives a solubility* of the Cu(OH)₂ to be ~1.77 x 10⁻⁷M => [Cu⁺²] ~1.77 x 10⁻⁷M and [OH⁻] = 2(1.77 x 10⁻⁷)M = 3.53 x 10⁻⁷M. The reaction of Ammonium Hydroxide and Copper(II) Sulfate will generate 1 x 10⁻⁴ mole Cu(OH)₂ as a precipitate but only 1.77 x 10⁻⁷ mole of the hydroxide will remain in 1 Liter of solution b/c of extreme limited solubility.
*Solubility of 1:2 ionization ratio salts = CubeRt(Ksp/4).
Answer: metabolic acidosis.
Explanation:
Anion Gap(AG) is the difference between positively charged ions and negatively charged ions. It is usually expressed in milliequivalents per litre of millimoles per litres.
Anion Gap is measured or calculated when there is a need to know the cause of metabolic acidosis. To
Anion Gap can be calculated with or without potassium.
(1). With potassium= ([Na^+] + [K^+]) − ([Cl^−] + [HCO^−3]).
From the question; client's lab values are sodium 166 mEq/L, potassium 5.0 mEq/L, chloride 115 mEq/L, and bicarbonate 35 mEq/L.
Slotting in the values, we have;
==>[ (166+5) - (115+35)] mEq/L.
(2). Without potassium:
==> [Na^+] - ([Cl^−] + [HCO^−3]).
==> [(166) - 115 + (35)] mEq/L
Normal Anion gap is 20 mEq/L(Calculating with Potassium) and 8-16 mEq/L (calculating without potassium).
Answer: i think maybe 10.
Explanation: