Answer:
P = 164 Atm
Explanation:
PV = nRT => P = nRT/V
n = 10.0 moles
R = 0.08206 L·Atm/mol·K
T = 27.0°C = 300 K
V = 1.50 Liters
P = (10.0 mol)(0.08206 L·Atm/mol·K )(300 K)/(1.50 Liters) = 164.12 Atm ≅ 164 Atm (3 sig. figs.)
Answer:
Q = 2260.44 j
Explanation:
Given data:
Mass of ice = 18 g
Initial temperature = -10 °C
Final temperature = 20°C
Heat absorbed by ice = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = Final temperature - initial temperature
ΔT = 20°C - (-10°C)
ΔT = 30°C
Specific heat of water = 2.00 j/g.°C
Q = 18 g × 4.186 j/g.°C × 30°C
Q = 2260.44 j
The average atomic mass of the imaginary element : 47.255 amu
<h3>Further explanation </h3>
The elements in nature have several types of isotopes
Isotopes are elements that have the same Atomic Number (Proton)
Atomic mass is the average atomic mass of all its isotopes
Mass atom X = mass isotope 1 . % + mass isotope 2.% ..
isotope E-47 47.011 amu, 87.34%
isotope E-48 48.008 amu, 6.895
isotope E-49 50.009 amu, 5.77%
The average atomic mass :

K + 02 ---> K20
4K + O2 ---> 2K2O
Answer: The moles of KIO cuboid titrated are 0.0002382
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
where,
n = moles of solute
= volume of solution in ml
Now put all the given values in the formula of molarity, we get
Therefore, the moles of KIO cuboid are 0.0002382