Answer:
13. 169π ft²
16. 34π mm
17. 12π in
18. 441π m²
Step-by-step explanation:
Circumference of a circle is calculated as follows:
C = 2π*r
Area of a circle is calculated as follows:
A = π*r²
where <em>r</em> is the radius of the circle
13. circumference of the circle: 26π ft
Then, its radius is:
26π = 2π*r
r = 26π/(2π) = 13 ft
A = π*13² = 169π ft²
16. area of the circle: 289π mm²
Then, its radius is:
289π = π*r²
r = √289
r = 17 mm
C = 2π*17 = 34π mm
17. area of the circle: 113.1 in²
Then, its radius is:
113.1 = π*r²
r = √(113.1/π)
r = 6 in
C = 2π*6 = 12π in
18. circumference of the circle: 131.95 m
Then, its radius is:
131.95 = 2π*r
r = 131.95/(2π)
r = 21 m
A = π*21² = 441π m²
Step-by-step explanation:
Area of remaining paper
= Area of rectangle - 2 * Area of semicircle
= Area of rectange - Area of circle
= (4in * 8in) - (π * 2in * 2in)
= 32in² - 4πin²
= 19.44in². (A)
Answer:
V ( Vcos 60° , Vsin60°) or V ( 2, 2√3)
Step-by-step explanation:
A vector and its components form a right triangle, then we need to get trigonometric functions ( sin and cos) of the angle of the module with x-axis
π/3 = 180⁰/3 = 60⁰ Angle between vector and positive x-axis
and sin 60⁰ = √3 /2 cos 60⁰ = 1/2
Let call V(x) component of vector v in x-axis, and V(y) component of vector v in y-axis then
V(x) = |v|*cos 60⁰ ⇒ V(x) = |v|*1/2 ⇒ V(x) = 4*1/2 ⇒ V(x) = 2
And
V(y) = |v|*sin 60⁰ ⇒ V(y) = |v|*√3/2 ⇒ V(y) = 4*√3/2 V(y) = 2*√3
V = (Vx,Vy) V ( Vcos 60° , Vsin60°) V ( 2, 2√3)
Answer:
(A), (D), and (E)
Step-by-step explanation:
In a quadratic function, the solutions are always on the x-axis, which means that it can be another word for x-intercept. Also, a zero and a root are the same thing, and they are both x-intercepts. Hope this helps!