Answer:
f(x)=(x-1)^2+5 with domain x>1 and range y>5 has inverse g(x)=sqrt(x-5)+1 with domain x>5 and range y>1.
Step-by-step explanation:
The function is a parabola when graphed. It is in vertex form f(x)=a(x-h)^2+k where (h,k) is vertex and a tells us if it's reflected or not or if it's stretched. The thing we need to notice is the vertex because if we cut the graph with a vertical line here the curve will be one to one. So the vertex is (1,5). Let's restrict the domain so x >1.
* if x>1, then x-1>0.
* Also since the parabola opens up, then y>5.
So let's solve y=(x-1)^2+5 for x.
Subtract 5 on both sides:
y-5=(x-1)^2
Take square root of both sides:
Plus/minus sqrt(y-5)=x-1
We want x-1>0:
Sqrt(y-5)=x-1
Add 1 on both sides:
Sqrt(y-5)+1=x
Swap x and y:
Sqrt(x-5)+1=y
x>5
y>1
Answer:
1+1=2
I don't know why you would ask that lol
Answer:
f(3) = -17
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = -5x - 2
f(3) is x = 3
<u>Step 2: Evaluate</u>
- Substitute in <em>x</em>: f(3) = -5(3) - 2
- Multiply: f(3) = -15 - 2
- Subtract: f(3) = -17
Answer:
no
Step-by-step explanation:
3x=-12
/3 /3
x=-4
:)
Answer:
C
Step-by-step explanation:
In order to be able to find the circumference in relation to radius, you have to use the formula C = 2πr
Hope this helped :)
