All categories

3 years ago

Solve (X + 6)(x - 4) = -16 O {-4, 6) O {-4, 2] O (-12, 22)

Mathematics

1 answer:

masya89 [10]3 years ago

6 0

Answer:

x=2 or x=−4

Step-by-step explanation:

Let's solve your equation step-by-step.

(x+6)(x−4)=−16

Step 1: Simplify both sides of the equation.

x2+2x−24=−16

Step 2: Subtract -16 from both sides.

x2+2x−24−(−16)=−16−(−16)

x2+2x−8=0

Step 3: Factor left side of equation.

(x−2)(x+4)=0

Step 4: Set factors equal to 0.

x−2=0 or x+4=0

x=2 or x=−4

You might be interested in

Curtis decided to go on a road trip to Canada. On the first day of his trip, he drove for 15 hours and traveled 1,005 miles. At

Radda [10]

Answer:

Step-by-step explanation:

1,005 / 15 = 67

3 0

3 years ago

Read 2 more answers

HELP HELP HELP Sally can paint a room in 4 hours. Joe can paint a room in 6 hours. How

Dmitry [639]

Answer:

2 hrs, 24 min

Step-by-step explanation:

Sally: in one hour, she can paint 1/4 of the room.

Joe: in one our, he can paint 1/6 of the room

Hour one: 1/4+1/6=3/12+2/12=5/12

1÷5/12=1*12/5=12/5

12/5= 2 & 2/5 hours, or 2.4 hours, or 2 hrs 24 minutes

6 0

2 years ago

Read 2 more answers

Here is a rectangle which has a width of x cm. x cm

miskamm [114]

Answer:

278.25 cm2

Step-by-step explanation:

If the width of the rectangle is x (cm), as the length is 8cm longer, so that the length of the rectangle is: x + 8 (cm).

In the attached image, we can see the length of each side. Total length of the sides are 90 cm.

=> (x + x + 8) + x + 8 + (x+8) + (x + x + 8) + x + 8 + (x +8) = 90

=> 8x + 48 = 90

=> 8x = 90 - 48 = 42

=> x =42/8 = 5.25 (cm)

=> The width of the rectangle is 5.25cm

=> The length of the rectangle is: 5.25 + 8 = 13.25 cm

=> The area of one rectangle is: Length x Width = 5.25 x 13.25 = 69.5625 cm2

As the 8-sided shape is made from 4 rectangles, so that:

Area of 8 sided shape = 4 x Area of the rectangle = 4 x 69.5625 = 278.25 cm2

6 0

3 years ago

Would appreciate the help !

aleksandr82 [10.1K]

This is one pathway to prove the identity.

Part 1

$\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{1}{\tan(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\cot(\theta) = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{\cos(\theta)}{\sin(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)*\sin(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)(1-\cos(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 2

$\frac{\sin^2(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)-\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-(\cos(\theta)-\cos^2(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-\cos(\theta)+\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 3

$\frac{\sin^2(\theta)+\cos^2(\theta)-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1}{\sin(\theta)} = \frac{1}{\sin(\theta)} \ \ {\checkmark}\\\\$

As the steps above show, the goal is to get both sides be the same identical expression. You should only work with one side to transform it into the other. In this case, the left side transforms while the right side stays fixed the entire time. The general rule is that you should convert the more complicated expression into a simpler form.

We use other previously established or proven trig identities to work through the steps. For example, I used the pythagorean identity $\sin^2(\theta)+\cos^2(\theta) = 1$ in the second to last step. I broke the steps into three parts to hopefully make it more manageable.