Answer:
a) Speedup gain is 1.428 times.
b) Speedup gain is 1.81 times.
Explanation:
in order to calculate the speedup again of an application that has a 60 percent parallel component using Anklahls Law is speedup which state that:

Where S is the portion of the application that must be performed serially, and N is the number of processing cores.
(a) For N = 2 processing cores, and a 60%, then S = 40% or 0.4
Thus, the speedup is:

Speedup gain is 1.428 times.
(b) For N = 4 processing cores and a 60%, then S = 40% or 0.4
Thus, the speedup is:

Speedup gain is 1.81 times.
Answer:
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Answer:
I grew up in the early internet stages. when i was young we would always have to sit at school, meetup somewhere, in town, or use the home phone. But when the internet was invented we could talk to each other through our computers at home. Old computers were so bulky and slow, but that was the coolest thing around. Now i can sit at home with my 20'' moniter on my 5g wifi and talking to my friends like theres no tomorrow. The internet has changed so much in the last years. If you were gonna tell me that one day ill be sitting at home playing games online and working from home on a laptop i would have told you that you were crazy.
Explanation: