First, solve within the parentheses. 18/6=3. Now solve the multiplication and division 1/2x6=3. The equation is now 3+9-3. Add and/or subtract from left to right. 3+9=12. 12-3=9. The answer is 9.
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Answer:
The probability that an athlete chosen is either a football player or a basketball player is 56%.
Step-by-step explanation:
Let the athletes which are Football player be 'A'
Let the athletes which are Basket ball player be 'B'
Given:
Football players (A) = 13%
Basketball players (B) = 52%
Both football and basket ball players = 9%
We need to find probability that an athlete chosen is either a football player or a basketball player.
Solution:
The probability that athlete is a football player = 
The probability that athlete is a basketball player = 
The probability that athlete is both basket ball player and football player = 
We have to find the probability that an athlete chosen is either a football player or a basketball player
.
Now we know that;

Hence The probability that an athlete chosen is either a football player or a basketball player is 56%.
100*I=PRT. Make T the subject =100I/PR
Substitute the figures in