(10x – 23)<br> WHAT IS THE VALUE OF X?<br> 137

vazorg [7]

To solve this problem, we are going to set up an equation. However, first we need to convert the percentages to decimals by dividing by 100.

15% = 0.15 , 7.5% = 0.075

Now, we should substitute in our given information into our equation and let our unknown value be equal to the variable x.

0.15(500) = 0.075x

Then, we should simplify our equation by multiplying together the two factors on the left side of the equation.

75 = 0.075x

Finally, we should divide both sides of the equation by 0.075 to get the variable x alone.

x = 1000

Therefore, your answer is 1000.

Hope this helps!

4 0

3 years ago

Read 2 more answers

Help meh pls!! plsss

xxMikexx [17]

The answer is C.379---------

6 0

2 years ago

Read 2 more answers

Solve using Fourier series.

Olin [163]

With $2L=\pi$ , the Fourier series expansion of $f(x)$ is

$\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos\dfrac{n\pi x}L+\sum_{n\ge1}b_n\sin\dfrac{n\pi x}L$
$\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos2nx+\sum_{n\ge1}b_n\sin2nx$

where the coefficients are obtained by computing

$\displaystyle a_0=\frac1L\int_0^{2L}f(x)\,\mathrm dx$
$\displaystyle a_0=\frac2\pi\int_0^\pi f(x)\,\mathrm dx$

$\displaystyle a_n=\frac1L\int_0^{2L}f(x)\cos\dfrac{n\pi x}L\,\mathrm dx$
$\displaystyle a_n=\frac2\pi\int_0^\pi f(x)\cos2nx\,\mathrm dx$

$\displaystyle b_n=\frac1L\int_0^{2L}f(x)\sin\dfrac{n\pi x}L\,\mathrm dx$
$\displaystyle b_n=\frac2\pi\int_0^\pi f(x)\sin2nx\,\mathrm dx$

You should end up with

$a_0=0$
$a_n=0$
(both due to the fact that $f(x)$ is odd)
$b_n=\dfrac1{3n}\left(2-\cos\dfrac{2n\pi}3-\cos\dfrac{4n\pi}3\right)$

Now the problem is that this expansion does not match the given one. As a matter of fact, since $f(x)$ is odd, there is no cosine series. So I'm starting to think this question is missing some initial details.

One possibility is that you're actually supposed to use the even extension of $f(x)$ , which is to say we're actually considering the function

$\varphi(x)=\begin{cases}\frac\pi3&\text{for }|x|\le\frac\pi3\\0&\text{for }\frac\pi3$

and enforcing a period of $2L=2\pi$ . Now, you should find that

$\varphi(x)\sim\dfrac2{\sqrt3}\left(\cos x-\dfrac{\cos5x}5+\dfrac{\cos7x}7-\dfrac{\cos11x}{11}+\cdots\right)$

The value of the sum can then be verified by choosing $x=0$ , which gives

$\varphi(0)=\dfrac\pi3=\dfrac2{\sqrt3}\left(1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots\right)$
$\implies\dfrac\pi{2\sqrt3}=1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots$

as required.

5 0

2 years ago

Whic

andreyandreev [35.5K]

Figure A which has two rays connected at a vertex is an angle in this scenario.

<h3>What is an Angle?</h3>

This is formed when two rays share a common endpoint with there being different types of angles.

The common endpoint shared forms a vertex which is why Figure A was chosen as the most appropriate choice.

Read more about Angle here brainly.com/question/25770607

#SPJ1

5 0

1 year ago

Someone pleas help 15 points if you so please

Elan Coil [88]

Answer:

man thats hard i dont even know

Step-by-step explanation:

7 0

2 years ago

(10x – 23) WHAT IS THE VALUE OF X? 137