Answer:
Therefore, our applicable set is: 0, 8, and 5. All of these numbers make the inequality true.
Step-by-step explanation:
x + 22 < 32
This problem is fairly simple! All we need to do is substitute each number given for x and compute to find out if the equation will be true! First what we need to do is plug in each number given into our variable x. Our numbers are: 0, 10, 8, 71, 15, and 5
x = 0
0 + 22 < 32
22 < 32
Is 22 less than 32? It is! So it belongs to the solution set.
x = 10
10 + 22 < 32
32 < 32
32 is equal to 32, not less than 32. A number cannot be itself and less than itself, thus x = 10 does not belong to the solution set.
x = 8
8 + 22 < 32
30 < 32
Is 30 less than 32? Yes! Since the inequality is true (that's what these kinds of equations are called) it belongs to the solution set.
x = 71
71 + 22 < 32
94 < 32
Is 94 less than 32? No. 71 does not belong to this solution set.
x = 15
15 + 22 < 32
37 < 32
37 is not less than 32. Therefore it doesn't belong to the solution set.
x = 5
5 + 22 < 32
27 < 32
Is 27 less than 32? Yes. Therefore, it belongs to the solution set.
Therefore, our applicable set is: 0, 8, and 5. All of these numbers make the inequality true.
