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3 years ago

How do I graph this linear equation y=3x+4

1 answer:

5 0

First mark a point at 4 on the y axis
Then because the slope is 3 you are going to rise three places up and one place to the right.
Use a ruler to connect the dots.
Hope this helps.

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A taxi company charges $1.00 for the first mile (or part of a mile) and 20 cents for each succeeding tenth of a mile (or part).

meriva

Step-by-step explanation:

solving functions separately.

1st: from given data taxi charges $1.00 for the first mile.so it is first rule of function.

$y_{1} =1 , 0$

2nd: the company charge $0.20 per tenth of a mile.so 2nd rule of the function will be

$y_{2} =1+0.2.10(x-1)$

simplifying

$y_{2} =1+2(x-1)$

$y_{2} =x+2x-2$

$y_{2} =x$ , $1$

piece wise function is f(x)={2 , 0<x<1

{x , 1<x<2

the graph of the function is given below

7 0

3 years ago

There are four white socks and six black socks in a drawer. What is the probability of selecting a white sock, not replacing it,

m_a_m_a [10]

Answer:

A: 1/3

Step-by-step explanation:

please mark this answer as brainlest

8 0

2 years ago

3) The distance between two villages is 1.9 km.

Dmitrij [34]

☽------------❀-------------☾

Hi there!

~

1:10000 would be the scale.

❀Hope this helped you!❀

☽------------❀-------------☾

3 0

3 years ago

100 POINTS PLS HELP write the value of six dimes as a fracition,with 100 as a demominator

BartSMP [9]

1 dimes are worth 10 cents.

Multiply.

6 * 10 = 60

Put in a fraction with the denominator given.

60/100

Reduce the fraction.

60/100

30/50

15/25

3/5

Best of Luck!

7 0

2 years ago

Read 2 more answers

Suppose you'd like to save enough money to pay cash for your next car. The goal is to save an extra $28,000 over the next 6 year

Anna35 [415]

Given:

• Amount to save, A = $28,000

• Time, t = 6 years

• Interest rate, r = 5.3% ==> 0.053

• Number of times compounded = quarterly = 4 times

Let's find the amount that must be deposited into the account quarterly.

Apply the formula:

$FV=P(\frac{(1+\frac{r}{n})^{nt}-1}{\frac{r}{n}})$

Where:

FV is the future value = $28,000

r = 0.053

n = 4

t = 6 years

Thus, we have:

$28000=P(\frac{(1+\frac{0.053}{4})^{4\times6}-1)}{\frac{0.053}{4}}$

Let's solve for P.

We have:

$\begin{gathered} 28000=P(\frac{(1+0.01325)^{24}-1}{0.01325}) \\ \\ 28000=P(\frac{(1.01325)^{24}-1)^{}}{0.01325}) \\ \\ 28000=P(\frac{1.371509114-1}{0.01325}) \\ \\ 28000=P(\frac{0.371509114}{0.01325}) \end{gathered}$

Solving further:

$28000=P(28.0384237)$

Divide both sides by 28.0384237:

$\begin{gathered} \frac{28000}{28.0384237}=\frac{P(28.0384237)}{28.0384237} \\ \\ 998.6=P \\ \\ P=998.6 \end{gathered}$

Therefore, the amount that must be deposited quarterly into the account is $998.60

ANSWER:

$998.60

8 0

1 year ago