3 years ago

How do I graph this linear equation y=3x+4

1 answer:

5 0

First mark a point at 4 on the y axis
Then because the slope is 3 you are going to rise three places up and one place to the right.
Use a ruler to connect the dots.
Hope this helps.

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A line is drawn so that it passes through the points (-3, -1) and (4, 2).

marishachu [46]

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(A) $\boxed{\bold{y=\frac{3}{7}x+\frac{2}{7}}}$

(B) $\boxed{\bold{2 \ = \ \frac{3}{7} * \ 4 \ + \ \frac{2}{7} }}$

Explanation:

(A) Slope: y = mx + b

m = 3/7

b = 2/7

Slope = $\bold{\frac{y_2-y_1}{x_2-x_1}}$

$\bold{\left(x_1,\:y_1\right)=\left(-3,\:-1\right),\:\left(x_2,\:y_2\right)=\left(4,\:2\right)}$

M = $\bold{\frac{2-\left(-1\right)}{4-\left(-3\right)}: \ \frac{3}{7} }$

Y intercept

$\bold{y=\frac{3}{7}x+b}$

Plug in $\bold{\left(-3,\:-1\right)\mathrm{:\:}\quad \:x=-3,\:y=-1}$

$\bold{-1=\frac{3}{7}\left(-3\right)+b}$

Isolate B

$\bold{-1=\frac{3}{7}\left(-3\right)+b}$

b = $\bold{\frac{2}{7} }$

(B) 4 = x, 2 = y

2 = 3/7 * 4 + 2/7

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