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BARSIC [14]
3 years ago
7

YOU WILL GET BRAINLIST AN 21 POINTS!!!!!!!1

Mathematics
2 answers:
lakkis [162]3 years ago
8 0

Answer:

0.64

Plz mark brainliest

Step-by-step explanation:

Alina [70]3 years ago
7 0

Answer:

The product would have 8 groups of 8 squares shaded out of 100

Step-by-step explanation:

8/100=0.08

8*8/100=64/100=0.64

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The sum of 7 angles of a decagon is 1170°. The 3 sides are equal to each other. Calculate the size of the other 3 angles.​
7nadin3 [17]

Answer:

180.....1888888888888888

5 0
3 years ago
Read 2 more answers
Solve for x.<br> 13(x-3) = 39<br> X=1<br> X=4<br> x=6<br> x=10
Valentin [98]
13 factored out is 13x - 39 add 39 to both sides it equals 13x=78 and 78 divided by 13 is 6 the anwser is x=6
7 0
3 years ago
What is 3/2=9/10k im having troble lots rly
tigry1 [53]

Answer:

k=  5 over 3  =1.667

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    (3)/(2)-((9)/(10)*k)=0

simplify 9/10

 3      9

 — -  (—— • k)  = 0  

 2     10

simplify 3/2

 3    9k

 — -  ——  = 0  

 2    10

   Find the Least Common Multiple

     The left denominator is :       2  

     The right denominator is :       10

Least Common Multiple:

     10

Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M  

   Denote the Left Multiplier by  Left_M  

   Denote the Right Multiplier by  Right_M  

   Denote the Left Deniminator by  L_Deno  

   Denote the Right Multiplier by  R_Deno  

  Left_M = L.C.M / L_Deno = 5

  Right_M = L.C.M / R_Deno = 1

Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      3 • 5

  ——————————————————  =   —————

        L.C.M              10  

  R. Mult. • R. Num.      9k

  ——————————————————  =   ——

        L.C.M             10

Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

3 • 5 - (9k)     15 - 9k

————————————  =  ———————

     10            10  

Pull out like factors :

  15 - 9k  =   -3 • (3k - 5)

-3 • (3k - 5)

 —————————————  = 0  

      10      

When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 -3•(3k-5)

 ————————— • 10 = 0 • 10

    10    

Now, on the left hand side, the  10  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  -3  •  (3k-5)  = 0

Solve :    -3   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solve  :    3k-5 = 0  

Add  5  to both sides of the equation :  

                     3k = 5

Divide both sides of the equation by 3:

                    k = 5/3 = 1.667

one solution was found

k = 5/3 = 1.667

hope it helps sry its so long

7 0
4 years ago
What can you conclude about the setting, based on this passage? Buck is in the north, where sled dogs are in demand. Buck is exp
Dovator [93]

Answer:

We can conclude that the setting is stationed somewhere in the north where it's very cold, so cold that they can use sled dogs. We can also assume it's winter time because it normally snows during the winter.

So the setting is in the north where it is cold, during the winter time.

7 0
2 years ago
Read 2 more answers
Will some one help me please will friend
aliina [53]
Add the equations,just the way they appear there.

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-- Add the '+y' and the '-y'.  Write the sum under the 'y's.
-- Add the '2' and the '4'. Write the sum under them, with n " = " sign
before it.

You should now have an equation with only 'x' in it and no 'y'.
You can easily solve that one and find out the value of 'x'.

Once you know the value of 'x', go back to either one of the original
equations, and plug the number-value of 'x' in place of 'x'.

You'll then have an equation with only 'y' in it and no 'x'.
You can easily solve that one and find out the value of 'y'. 


7 0
4 years ago
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