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GenaCL600 [577]
3 years ago
9

Marco has drawn a line to represent the perpendicular cross-section of the triangular prism. Is he correct? Explain. triangular

prism lying on a rectangular face and a line drawn along the slant height of the triangle Yes, the line should be perpendicular to one of the rectangular faces Yes, the line should be perpendicular to the triangular faces No, the line should be perpendicular to one of the rectangular faces No, the line should be perpendicular to the triangular faces

Mathematics
2 answers:
evablogger [386]3 years ago
8 0

Answer:

The correct option is;

Yes, the line should be perpendicular to one of the rectangular faces

Step-by-step explanation:

The given information are;

A triangular prism lying on a rectangular base and a line drawn along the slant height

A perpendicular bisector should therefore be perpendicular with reference to the base of the triangular prism such that the cross section will be congruent to the triangular faces

Therefore Marco is correct and the correct option is yes, the line should be perpendicular to one of the rectangular faces (the face the prism is lying on).

anastassius [24]3 years ago
3 0

Answer:

D. " No, the line should be perpendicular to the triangular faces"

Step-by-step explanation:

I took the test before and got it correct but if you would like an explanation:

A perpendicular cross section is meant to be perpendicular to the base of a 3-dimensional figure. The bases of triangular prisms are the triangles at either ends, and the rectangles make up the remaining faces.

Marco drew the line perpendicular to the rectangle faces because it was lying on it's side, he presumed it to be the base. But he was incorrect, the line should be parallel to the faces, perpendicular to the base. Therefore, option D is correct.

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Step-by-step explanation:

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the second way is the regular way

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3 years ago
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Answer:

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Step-by-step explanation:

Given

1\ yard = 0.914\ meter

Required

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1\ yard = 0.914\ meter

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1\ meter = 1.09409190372\ yard

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6 0
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Answer:

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