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3 years ago

Which inequality is true for x = 3?

1 answer:

3 0

Hello!

You can put 3 in for x and see which on is true
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Inequality A

6(3) + 18 < 30

Multiply

18 + 18 < 30

Add

36 < 30

This is not true so this is not the answer
------------------------------------------------------------------------------------------------------
Inequality B

8(3) - 4 < 10

Multiply

24 - 4 < 10

Subtract

20 < 10

This is not true so this is not the answer
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Inequality C

10(3) + 10 < 37

Multiply

30 + 10 < 37

Add

40 < 37

This is not true so this is not the answer
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Inequality D

15(3) - 10 < 40

Multiply

45 - 10 < 40

Subtract

35 < 40

This is true so this is the answer
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The answer is D) 15x - 10 < 40

Hope this helps!

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What is the volume of the cylinder? Do not round your answer. (Use 3.14 for π .)

vitfil [10]

Answer:

When I used a cylinder calculator I got 6785.84 yd^3

Step-by-step explanation:

7 0

3 years ago

37-(-3)squared+30\(-3)x2

vampirchik [111]

Simplify:
37 - (-3)^2 + 30/(-3)x^2
= 37 + - 9 + - 10x^2

Combine like terms:
= 37 + - 9 + - 10x^2
= ( - 10x^2) + (37 + - 90
= - 10X^2 + 28
Answer: - 10x^2 + 28

To Factor:
37 - (- 3)^2 + 30/- 3x^2

- 10x^2 + 28
- 2(5x^2 - 14)

Answer: - 2(5x^2 - 14)

I simplify, and factor, because, you didn't really specify what you wanted help on with this equation. - Thanks -

Hope that helps!!!!

6 0

3 years ago

Given segments AB and CD intersect at E.

nata0808 [166]

The length of a segment is the distance between its endpoints.

$\mathbf{AB = 3\sqrt{2}}$
AB and CD are not congruent
AB does not bisect CD
CD does not bisect AB

(a) Length of AB

We have:

$\mathbf{A = (1,2)}$

$\mathbf{B = (4,5)}$

The length of AB is calculated using the following distance formula

$\mathbf{AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

So, we have:

$\mathbf{AB = \sqrt{(1 - 4)^2 + (2 - 5)^2}}$

$\mathbf{AB = \sqrt{18}}$

Simplify

$\mathbf{AB = 3\sqrt{2}}$

(b) Are AB and CD congruent

First, we calculate the length of CD using:

$\mathbf{CD = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

Where:

$\mathbf{C = (2, 4)}$

$\mathbf{D = (2, 1)}$

So, we have:

$\mathbf{CD = \sqrt{(2 -2)^2 + (4 - 1)^2}}$

$\mathbf{CD = \sqrt{9}}$

$\mathbf{CD = 3}$

By comparison

$\mathbf{CD \ne AB}$

Hence, AB and CD are not congruent

(c) AB bisects CD or not?

If AB bisects CD, then:

$\mathbf{AB = \frac 12 \times CD}$

The above equation is not true, because:

$\mathbf{3\sqrt 2 \ne \frac 12 \times 3}$

Hence, AB does not bisect CD

(d) CD bisects AB or not?

If CD bisects AB, then:

$\mathbf{CD = \frac 12 \times AB}$

The above equation is not true, because:

$\mathbf{3 \ne \frac 12 \times 3\sqrt 2}$

Hence, CD does not bisect AB

Read more about lengths and bisections at:

brainly.com/question/20837270

7 0

2 years ago

What mathmatical concepts did e.harrison use to support the claim?

sergey [27]

umm, i the the desuetude what no one sec.

4 0

3 years ago

PLS HELP ASAP. QUESTION IN PICTURE

Anuta_ua [19.1K]

Answer: 50 degrees

Step-by-step explanation:

This is actually quite simple using the exterior angle theory

"The exterior angle theorem states that the measure of an exterior angle is equal to the sum of the measures of the two remote interior angles of the triangle"

In this case the exterior angle is 120 degrees, basically what the theorem states is that it the angle that you see outside the triangle equals the angle measurements of the 2 angles opposite of it, so just create an equation because you know 2 of the variables

120=70+x

120-70=x

Angle x = 50 degrees

4 0

2 years ago