Every function is a relation because the numbers have relationships but not every relation is a function because for it to be a function there has to be one y fo every x if any x(input) has more than one y(output) it's not a function
Answer:
Im confused what your trying to get at is there a picture or something
Step-by-step explanation:
Answer:
16
Step-by-step explanation:
If X is the centroid that means that EC is a median along with the other lines that intersect inside the triangle. Medians drawn from a triangle have a special rule; this rule is that all medians have a 2:1 ratio between the different sections of one median. For example, EC is one median with the two sections XC and EX. Therefore XC and EX have a 2:1, with the 2 representing the longer section closest to the vertex. This means that XC is double EX, so to find XC simply double EX measurement, which is 8. So XC must equal 16.
Let's start with a picture.
We see RST is smaller, and BC is parallel to but in the opposite direction to its corresponding segment ST. Both have slope -1.
If we look at the difference of points (technically called vectors but we don't have to go there) we get
C-B=(-2,2)
T-S=(1,-1)
Without further calculation we can see T-S is half the length of C-B.
The problem asks for a dilation followed by a reflection. We know the dilation scale is k=1/2 because the new triangle is half the size.
After dilation we get A'B'C':
A'(3,2), B'(-1,0), C'(-2,1)
We see now we need a reflection that flips the coordinates x and y. That's the +45° line through the origin, namely y=x.
Answer: k=1/2, y=x
Answer:
A. Minimum = 54, Q1= 69.5, Median = 75, Q3= 106, Maximum = 183
Step-by-step explanation:
Arranging the data set in order from least to greastest we get:
54, 68, 71, 72, 75, 84, 104, 108, 183
From this, we can see that the minimum value is 54 and the maximum value is 183.
Taking a number off one by one on each side of the data set gives the median. In the middle lies 75, so that is our median
To find quartile ranges, split the data set into two where the median lies, then, find the median of those two data sets. The medians will be the values of the upper (Q3) and lower quartiles (Q1).
Q1: 54, 68, 71, 72
68 + 71 = 139
139 ÷ 2 = 69.5
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Q3: 84, 104, 108, 183
104 + 108 = 212
212 ÷ 2 = 106
Option A is the only answer with all of these values, therefore, it is the answer.
hope this helps!
