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Maslowich
3 years ago
9

|x+2|+4=11 A) x=5,-9

Mathematics
2 answers:
Lisa [10]3 years ago
8 0

Answer:

the mod always gives positive answers

so the answer will be

Step-by-step explanation:

x+2+4=11

x+6=11

x=11-6

x=5

answer is x is 5

Pavel [41]3 years ago
3 0

Answer:

x=5,9

Step-by-step explanation:

|x+2|+4=11

|x+2| = 7

next you get two answers by adding two or subtracting two. SO the right answer should be 5 and 9. A is wrong . I DONT SEE THE OTHER ANSWER CHOICES BUT THIS IS WHAT I GOT.

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The sum of 3 consecutive odd numbers is 51. what is the second number in this sequence
cricket20 [7]

Answer:

17

Step-by-step explanation:

since it is in the middle you can just divide by 3 since one will be greater and one will be less so 51/3=17

6 0
3 years ago
Read 2 more answers
Choose the equation that represents the graph below.
PtichkaEL [24]
So the question ask to calculate and find the equation that could represent the graph that is shown in your problem. In getting the answer to this, you must use the formula of the slope intercept form and get the value of the slope. So the answer would be letter D. y=x+3.
3 0
3 years ago
The area of one of the smaller circles is 8/ in². Find the area of the shaded region.
Ksju [112]

Answer:

Area of shaded region = 16π in² (D)

Step-by-step explanation:

The question is incomplete without the diagram if the circles. Find attached the diagram used in solving the question.

Area of the smaller circle = 8π in²

Area of a circle = πr²

πr² = 8π

r² =8

r = √8 = 2√2

From the diagram, there are two smaller circles in a bigger circle.

The radius of the bigger circle (R) is 2times the radius of the smaller circle (r)

R = 2r

Area of bigger circle = πR²

= π×(2r)² =   π×(2×2√2)²

= π×(4√2)² = π×16×(√2)²

Area of bigger circle = π×16×2

Area of bigger circle = 32π in²

Since there are two smaller circles in a bigger circle

Area of shaded region = Area of bigger circle -2(area of smaller circles)

Area of shaded region = 32π in² - 2(8π in²)

Area of shaded region = 32π in² - 16π in²

Area of shaded region = 16π in²

8 0
3 years ago
Help plz!!!!!!!!!!!!!!!!!!!!
lukranit [14]

Answer:

6

Step-by-step explanation:

lower quarter is 10

higher quarter is 16

16-10=6

8 0
3 years ago
Read 2 more answers
Bill planted 647 tulip bulbs in his flower garden.He had to plant the bulbs in rows of 20.how many rows was bill able to plant?w
Angelina_Jolie [31]

Answer:

please pretty please mark brainlist

Step-by-step explanation:

number of plants = 647

number of plants in 1 rows = 20

number of rows =

647 ÷ 20 = 32 and remainder = 7 =>

647 = 32 × 20 + 7 =>

647/20 =

(32 × 20 + 7) / 20 =

32 + 7/20 =

32 7/20

5 0
3 years ago
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