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romanna [79]
3 years ago
5

Manny observed a Northern Gannet, a deep diving seabird, hovering at a height of 10 meters above the ocean surface. The bird the

n dove into the water, diving to a depth of 16 meters before coming to the surface. The dive can be modeled by a quadratic function, y = x2 – 10.3x + 10, where x represents the time the dive lasted in seconds and y represents the height of the bird in meters. Use the graphing calculator to graph the equation. After how many seconds did the bird surface? Round your answer to the nearest tenth. seconds
Mathematics
1 answer:
koban [17]3 years ago
6 0

Answer:

9.2 seconds

Step-by-step explanation:

got it right on edg 2020

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A sample of 18 small bags of the same brand of candies was selected. Assume that the population distribution of bag weights is n
ki77a [65]

Answer:

a)

i.  x=- - - - - -

ii.  o=- - - - - -

iii.  Sx=- - - - -

b) The random variable X signifies the weights of the bags of candies which are selected at random.  

c) The statistics variable X  is a measure on a sample that is used as an estimate of the population mean.X  is the mean weight of the 16 bags of candies that were selected.

d) The distribution needed for this problem is normal distribution with parameters  because the population standard deviation is known.

N(X, o/\sqrt{n})

So, the distribution is  

N(2, 0.12/\sqrt{16})

e)

i. The 90% confidence interval for the population mean weight of the candies is  1.9589 , 2.0411

iii. The error bound is 0.0411

f)

i. The 98% confidence interval for the population mean weight of the candies is  1.9418 , 2.0582

iii. The error bound is 0.0582

g) The difference in the confidence intervals in part (f) and part (e) is of the level of confidence. The change is, the change in the area being calculated for the normal distribution. Therefore, the larger confidence level results in larger area and larger interval.

Hence the interval in part  is larger than the one in part (e).

h) The interval in part (f) signifies that with 98% confidence that the population mean weight of the bag of candies lies between 1.942 ounce and 2.058 ounce.

Step-by-step explanation:

a)

i.  x=- - - - - -

ii.  o=- - - - - -

iii.  Sx=- - - - -

b) The random variable X signifies the weights of the bags of candies which are selected at random.  

c) The statistics variable X  is a measure on a sample that is used as an estimate of the population mean.X  is the mean weight of the 16 bags of candies that were selected.

d) The distribution needed for this problem is normal distribution with parameters  because the population standard deviation is known.

N(X, o/\sqrt{n})

So, the distribution is  

N(2, 0.12/\sqrt{16})

e)

i. The 90% confidence interval for the population mean weight of the candies is  1.9589 , 2.0411

iii. The error bound is 0.0411

f)

i. The 98% confidence interval for the population mean weight of the candies is  1.9418 , 2.0582

iii. The error bound is 0.0582

g) The difference in the confidence intervals in part (f) and part (e) is of the level of confidence. The change is, the change in the area being calculated for the normal distribution. Therefore, the larger confidence level results in larger area and larger interval.

Hence the interval in part  is larger than the one in part (e).

h) The interval in part (f) signifies that with 98% confidence that the population mean weight of the bag of candies lies between 1.942 ounce and 2.058 ounce.

5 0
2 years ago
1 - 5x = -5x + 1<br> Help pls solve for x
Vilka [71]

Answer:

x can be all real numbers

Step-by-step explanation:

1 - 5x = -5x + 1

-5x+5x=1-1

0=0

4 0
3 years ago
Read 2 more answers
Select the correct answer
Alexxx [7]

Answer:

The y intercept is 80 and the line of the best fit is -3/5

Step-by-step explanation:

5 0
3 years ago
What is solution 7x+5y=-24 and 4x+y=42?
LenKa [72]
7x+5y=-24 (1)
   4x+y=42 (2)

multiply equation (2) by 5 to get
20x+5y=210 (3)

then calculate (3)-(2) which gives you
13x=234 hence x=18
then substitute for x in either equation to get y=-30
6 0
3 years ago
Read 2 more answers
What is the GCF of (8x-6) <br><br>sos T-T
makvit [3.9K]

Hi student, let me help you out! :)

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

We are asked to find the G.C.F. of 8x-6.

\triangle~\fbox{\bf{KEY:}}

  • G.C.F. stands for Greatest Common Factor.

So what is the G.C.F. of 8x-6? We can list all of their common factors and then select the greatest one, like so:

\longmapsto\bf{Factors\;of\;8x:} 1, 2, 4, 8, x

\longmapsto\bf{Factors\;of\;-6:} -1, 1, 2, -3, 3, -6, 6

So the GCF is:

2

Now, we can also factor it out by placing it outside the parentheses ():

2(4x-3)

See, we factored it out by dividing both terms of the expression by the G.C.F.

\ddot\bigstar Remember this...

\fbox{\bf{We\;factor\;out\;the\;G.C.F.\;by\;dividing\;all\;the\;terms\;of\;the\;expression\;by\;it}}

Hope this helps you out! :D

Ask in comments if any queries arise.

~Just a smiley person helping fellow students :)

6 0
2 years ago
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