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3 years ago

Consider the transformation given by the mapping (x, y) to (2x, 4y). Is this

1 answer:

6 0

It’s a transformation because you can move 2 to the right then up 4 to get that easily. It cannot be a dilation because you can’t multiply/divide to get those numbers.

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Find the mean absolute deviation of the set of data. 4, 5, 8, 8, 10 (I also need on this)

Klio2033 [76]

Answer:

MAD = 0

Step-by-step explanation:

When I calculated this by hand I got 0. To find the MAD:

1. You first need to find the mean of the numbers.

4 + 5 + 8 + 8 + 10 = 35

35/5 = 7

the mean value = 7

2. Then you must find the absolute value of the difference between each data value and the mean: |data value – mean|

(4 - 7) = -3

(5 - 7) = -2

(8 - 7) = 1

(10 - 7) = 3

3. Add the difference values up

(-3) + (-2) + 1 + 1 +3 = 0

4. Divide the sum of the absolute values of the differences by the number of data values.

0/5 = 0

3 0

3 years ago

What is the value of point H on the number line? A. 3/5 B. 2.6 C. 5/3 D. 1.4

mario62 [17]

I believe that it’s D

8 0

2 years ago

Read 2 more answers

Which would be the best trend line for the given data set?

PSYCHO15rus [73]

I believe the correct answer would be a if it’s not remove my answer

6 0

3 years ago

Read 2 more answers

Find the third side in simplest radicle form: 8 and 34

zysi [14]

Answer:

7 $\sqrt{2}$

Step-by-step explanation:

$\sqrt{98}$ = 7 $\sqrt{2}$

5 0

2 years ago

The ability to find a job after graduation is very important to GSU students as it is to the students at most colleges and unive

gtnhenbr [62]

Answer: (0.8468, 0.8764)

Step-by-step explanation:

Formula to find the confidence interval for population proportion is given by :-

$\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

, where $\hat{p}$ = sample proportion.

z* = Critical value

n= Sample size.

Let p be the true proportion of GSU Juniors who believe that they will, immediately, be employed after graduation.

Given : Sample size = 3597

Number of students believe that they will find a job immediately after graduation= 3099

Then, $\hat{p}=\dfrac{3099}{3597}\approx0.8616$

We know that , Critical value for 99% confidence interval = z*=2.576 (By z-table)

The 99 % confidence interval for the proportion of GSU Juniors who believe that they will, immediately, be employed after graduation will be

$0.8616\pm(2.576)\sqrt{\dfrac{0.8616(1-0.8616)}{3597}}$

$0.8616\pm (2.576)\sqrt{0.0000331513594662}$

$\approx0.8616\pm0.0148\\\\=(0.8616-0.0148,\ 0.8616+0.0148)=(0.8468,\ 0.8764)$

Hence, the 99 % confidence interval for the proportion of GSU Juniors who believe that they will, immediately, be employed after graduation. = (0.8468, 0.8764)

4 0

3 years ago