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worty [1.4K]
3 years ago
13

The popularity of the Gutenberg press in Europe made books more accessible and motivated people to want to learn how to write. p

aint. read. travel.
Mathematics
1 answer:
Ainat [17]3 years ago
4 0

Answer:

read.

Step-by-step explanation:

The popularity of the Gutenberg press in Europe made books more accessible and motivated people want to learn how to READ.

This is evident in the fact that Johannes Gutenberg who was widely known as a printer was famous for inventing a means of producing books at a cheaper cost and portable size that is also durable and easy for distribution.

The result of this invention led to an increase in the availability of books and thereby enhance and motivate more people, not just the elites, to have access to books and READ them.

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5√-54 in simplest radical form
olga nikolaevna [1]

The answer is 15i radical 6

3 0
3 years ago
Read 2 more answers
Factorization of:
zubka84 [21]

Answer:

Step-by-step explanation:

2800: 2 * 2 * 2 * 2 * 5 * 5 * 7

75: 3 * 5 * 5

168: 2 * 2* 2 * 3 * 7

It's not really multiplication. It's more division.

Try 2800 as a sample. What you are trying to do is break this down into primes. The first prime is 2

2800/2 = 1400

1400 / 2 = 700

700 / 2 = 350

350 / 2 = 175. That's the end of what the 2s can do.

175 / 5 = 35

35/ 5 = 7 7 is a prime. You are done. Now run up the ladder.

2800: 2 * 2 * 2 * 2 * 5 * 5 * 7

75 is not an even number. It has no 2s. Go to 3

75 / 3 = 25.

25 / 5 = 5

That's the end

75: 3 * 5 * 5

Your calculator can be of great help. The rule is keep factoring until you get a decimal remainder. Move on to the next prime. Stop when the last division gives you a prime.

3 0
3 years ago
What are the solutions for x when y is equal to 0 in the quadratic function y=x^2-8x
Elena L [17]
I would use the quadratic formula for this:

  x = -b ± √b² - 4ac over 2a
  x = 8 ± √64 - 4(1)(0) over 2(1)
  x = 8 ± √64 over 2
  x = 8 <span>± 8 over 2 [simplify]
  x = 4 </span><span>± 4
     x1 = 4 + 4    x2 = 4 - 4
     x1 = 8          x2 = 0


Thus, the solutions for x would be 0 and 8.</span>
5 0
3 years ago
Divide.
bonufazy [111]

Answer:

-3

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Let alpha and beta be conjugate complex numbers such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}
miskamm [114]

Answer:

-3+i\sqrt{3} , 1+\sqrt{3}

Step-by-step explanation:

Given that alpha and beta be conjugate complex numbers

such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}.

Let

\alpha = x+iy\\\beta = x-iy

since they are conjugates

\alpha-\beta = x+iy-(x-iy)\\= 2iy= 2i\sqrt{3} \\y =\sqrt{3}

\frac{\alpha}{\beta^2} }\\=\frac{x+i\sqrt{3} }{(x-i\sqrt{3})^2} \\=\frac{x+i\sqrt{3}}{x^2-3-2i\sqrt{3}} \\=\frac{x+i\sqrt{3}((x^2-3+2i\sqrt{3}) }{(x^2-3-2i\sqrt{3)}(x^2-3-2i\sqrt{3})}

Imaginary part of the above =0

i.e. \sqrt{3} (x^2-3)+2x\sqrt{3} =0\\x^2+2x-3=0\\(x+3)(x-1) =0\\x=-3,1

So the value of alpha = -3+i\sqrt{3} , 1+\sqrt{3}

3 0
3 years ago
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